Suppose 250 subjects are treated with a drug that is used to treat pain and 50 of them developed nausea. Use a 0.05 significance level to test the claim that more than 20% of users develop nausea.
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Q: suppose 223 subjects are treated with a drug that is used to treat pain and 52 of them developed…
A: Null Hypothesis: A hypothesis which is tested for plausible rejection is called the Null Hypothesis…
Q: Suppose 221 subjects are treated with a drug that is used to treat pain and 52 of them developed…
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Q: In a previous poll, 39% of adults with children under the age of 18 reported that their family ate…
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A: Introduction: Consider that p is the true proportion of only children among the children in the…
Q: Suppose 242 subjects are treated with a drug that is used to treat pain and 50 of them developed…
A: Given that n=242 , X=50 , p=20%=0.20
Q: Suppose 243 subjects are treated with a drug that is used to treat pain and 50 of them developed…
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A: X=275, n=500, p=60%, level of signicance=1%
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A: Solution: Given information: p=7%= 7100=0.07q=1-p= 0.93x= 45n= 950p^= xn=45950=0.0474α=0.05
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- In a previous poll, 46% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 515 of 1172 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the a= 0.05 significance level. Because npo (1- Po) = V 10 and the sample size is V 5% of the population size, and the sample v the requirements for testing the hypothesis v satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? Ho: versus H, (Type integers or decimals. Do not round.) Find the test statistic, Zo- Zo (Round to two decimal places as needed.) Find the P-value. P-value = (Round to three decimal places as needed.) Is there sufficient evidence that the proportion of families with children…A simple random sample of 300 men included 71 who smoke, and a simple random sample of 310 women included 68 who smoke. Use a .05 level of significance to test the claim that the proportion of men who smoke is greater than the proportion of women who smoke.In a previous poll, 41% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 461 of 1173 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the a = 0.05 significance level. Because npo (1-Po) = 10 and the sample size is V 5% of the population size, and the sample the requirements for testing the hypothesis satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? V versus H, Но (Type integers or decimals. Do not round.) Find the test statistic, zo- Zn = (Round to two decimal places as needed.) Find the P-value. P-value = (Round to three decimal places as needed.) Is there sufficient evidence that the proportion of families with children…
- A company claims that at least 94% of equipment supplied to a manufacturer is within specifications. A test of a sample of 200 pieces of equipment showed that 27 of them were faulty. Test their claim at the 5% significance level?A common idea is that people can temporarily postponed death to survive a major holiday or important event. A study found that there were 6907 deaths before Thanksgiving and 5739 deaths after Thanksgiving. Test the claim at the 0.05 significance level that the proportion of deaths in the week before Thanksgiving is less that 0.5. Based on your result, does it appear that peole can temporarily postpone death to survive the Thanksgiving holiday?In a 2005 study 2205 adolescents aged 12 - 19 years old were give a treadmill test to check their cardiovascular health. 750 of the subjects were determined to have poor cardiovascular fitness. The researchers want to claim that more than 30% of adolescents have poor cardiovascular health (with a 5% level of significance). The research hypothesis is Ha:p>0.30. Find the test statistic, p-value, and state your conclusion.
- In a previous poll, 39% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 422 of 1145 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the x = 0.01 significance level. Because npo (1-Po) = 272.4 > 10 and the sample size is the hypothesis are satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? Ho: P = versus H₁: ▼ V (Type integers or decimals. Do not round.) Find the test statistic, Zo- C less than 5% of the population size, and the sample is given to be random, the requirements for testing Zo = (Round to two decimal places as needed.) Find the P-value. P-value = (Round to three decimal places as needed.) Is there sufficient…At CPU, it is estimated that fewer than 25% of the students have cars on campus. Does this seem to be a valid estimate if, a random sample of 90 college students, 28 are found to have cars? Use a 0.05 level of significance.In a previous poll, 38% of adults with children under the age of 18 reported that their family ate dinner together seven nights. suppose that, in a more recent poll, 399 of 1099 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. is there sufficient evidence that the proportion of families with children under the age of 18 who eat diner together seven nights a week has decreased? use the a=0.05 significance level
- In a certain school district, it was observed that 29% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 130 out of 373 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.05 level of significance. What is the hypothesized population proportion for this test? P =0.34 (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol) Based on the statement of this problem, how many tails would this hypothesis test have? one-tailed test two-tailed test Choose the correct pair of hypotheses for this situation: (C) (В) (A) Ho: p 0.29 Ho:p 0.29 Ho:p 0.29 H p 0.349 Ha p (F) (E) 0.349 (A) (B) (C) (D) (E) (F) N a e WIn a previous poll, 37% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 396 of 1132 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use the a= 0.05 significance level. Because npo (1-pPo) = 10 and the sample size is (Round to one decimal place as needed.) 5% of the population size, and the sample V the requirements for testing the hypothesis V satisfied What are the null and alternative hypotheses? V versus H, O Ho (Type integers or decimals. Do not round.) Find the test statistic, Zo Z0= (Round to two decimal places as needed.) Find the P-value P-value = (Round to three decimal places as needed.) Is there sufficient evidence that the proportion of families with children…