In a Fraunhofer diffraction experiment, a collimated light beam falls normally on a slit with 0.2mmwide. A thin lens placed just behind the slit focuses the diffracted light on a screen located at thefocal plane of the lens (f = 300cm). The distance between the 1st and 2nd minimum of thediffraction fringe pattern is 0.885cm.1) Calculate the wavelength of the incident light beam.2) If repeating this experiment using a soft X-ray beam with wavelength λ = 4nm 4 x10-3 μm, what will be the distance between the 1st and the 2nd minimum in the diffractionfringe pattern?www.di

Position of minimum in Fraunhofer diffraction: The position of minimum in Fraunhofer diffraction is…

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