In a double slit experiment, the distance between the slits is 0.2 mm and the distance to the screen is 150 cm. What is the phase difference (in degrees) between the waves from the two slits arriving at a point P when the angular distance of P is 10° relative to the central peak, and the wavelength is 500 nm? (Convert your result so the angle is between 0 and 360°.) a. 145° b. 155° 165° c. d. 135° 95° e. ANS: C PTS: 3 DIF: Challenging
In a double slit experiment, the distance between the slits is 0.2 mm and the distance to the screen is 150 cm. What is the phase difference (in degrees) between the waves from the two slits arriving at a point P when the angular distance of P is 10° relative to the central peak, and the wavelength is 500 nm? (Convert your result so the angle is between 0 and 360°.) a. 145° b. 155° 165° c. d. 135° 95° e. ANS: C PTS: 3 DIF: Challenging
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I already know the answer to this practice problem, and it is shown is the image. I do not know how to get to the answer though, so seeing the steps and equations would be much appreciated.
Transcribed Image Text:In a double slit experiment, the distance between the slits is 0.2 mm and the distance to the screen is 150 cm. What is the phase difference (in degrees) between the waves from the two slits arriving at a
point P when the angular distance of P is 10° relative to the central peak, and the wavelength is 500 nm? (Convert your result so the angle is between 0 and 360°.)
a.
145°
b.
155°
165°
c.
d.
135°
95°
e.
ANS: C
PTS: 3
DIF: Challenging
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