### Genetics Practice Problem**Question:**In a cross of AABbccddEe × AaBbCcDdee, what proportion of the offspring will show dominant phenotypes for the first three traits (controlled by A, B, and C) and recessive phenotypes for the last two traits (controlled by D and E)?**Options:**- ○ 3/32- ○ 1/64- ○ 3/64- ○ 1/32- ○ 9/64**Explanation:**In this genetics problem, we are given the genotypes of two parents for five traits and asked to determine the resulting phenotypes in their offspring. Specifically, we are looking for offspring with dominant phenotypes for the first three traits and recessive phenotypes for the last two traits.### Steps to Solve:1. **Identify Genotypes and Phenotypes:** - Dominant phenotypes for A (AA or Aa) - Dominant phenotypes for B (BB or Bb) - Dominant phenotypes for C (CC or Cc) - Recessive phenotypes for D (dd only) - Recessive phenotypes for E (ee only)2. **Calculate Probabilities for Each Trait:** - For A: A x A from AABbccddEe x Aa Bb Cc Dd ee gives 1 (AABb or Aa depending on the cross, but all will show dominant phenotype). - For B: Bb x BB or Bb from cross gives 1/2 (dominant phenotype). - For C: Cc x Cc from cross gives 3/4 (dominant phenotype). - For D: dd from Dd x dd from cross gives 1/2 (recessive phenotype). - For E: ee from Ee x ee from cross gives 1/2 (recessive phenotype).3. **Combine the Probabilities:** - Calculate the combined probability: 1 (A) x 1/2 (B) x 3/4 (C) x 1/2 (D) x 1/2 (E) = 3/32.### Answer:- **Correct Proportion: 3/32**This method allows us to determine the proportion of offspring that will display the desired combination of phenotypes.

Name: ### Genetics Practice Problem**Question:**In a cross of AABbccddEe ×
Uploaded: 2024-03-20T06:43:04.000Z
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Description: ### Genetics Practice Problem**Question:**In a cross of AABbccddEe × AaBbCcDdee, what proportion of the offspring will show dominant phenotypes for the first three traits (controlled by A, B, and C) and recessive phenotypes for the last two traits (