In a completely randomized design, eight experimental units were used for each of the five levels of the factor. Consider the following ANOVA table.Sourceof VariationTreatmentsErrorTotalSumof Squares300110410Degreesof Freedom##Ho: M₁ M₂ M3 M4 M5M5На: M1 = M2 = M3=M44(a) What hypotheses are implied in this problem?Ho: Not all the population means are equal.Ha: M₁ = M₂ = M3 = M4 = M5=35Ho: M₁ = M₂ = M3 = M4 = M5H₂: Not all the population means are equal.Ho: M₁ = M₂ = M3 = μ₁4 = M5Ha: M₁ M₂ M3 M4 M5# # #39MeanSquareHo:: At least two of the population means are equal.H₂: At least two of the population means are different.753.14F23.86p-value0.0000(b) At the α = 0.05 level of significance, can we reject the null hypothesis in part (a)? Explain.Because the p-value > α = 0.05, we cannot reject Ho.Because the p-value < α = 0.05, we cannot reject Ho.Because the p-value > α = 0.05, we can reject Ho.Because the p-value ≤ a = 0.05, we can reject Ho.

p-value is probability of measure of extremity of observed result.P value smaller than level of…

Answered: In a completely randomized design,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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