In a circuit that contains only resistors in series, the current is the same throughout the circuit (remember that current is conserved!). The amount of current in the circuit is determined by the potential difference (or em f) of the battery and the equivalent resistance, Req, of the circuit. We can therefore write Ohm's Law as DeltaV = IReq. Assume the batteries supply a potential difference of DeltaV = 3.0 V, and use the currents measured in circuits 3a, 3b, and 3c to determine the equivalent resistance in each circuit. Please show the calculation of each. R1 = 150 ohm, R2 = 230 ohm R3 = 270 ohms (don't believe question should need these but providing anyways) Current Measured Current through R1 in 3a (Only resistor 1) Ir1= 0.01 amp Current through R1 in 3b (Resistor 1 and 2) Ir1= 0.0032 amp Current through R1 in 3c (Resistor 1, 2 and 3) Ir1 = 0.002 amp
1. In a circuit that contains only resistors in series, the current is the same throughout the circuit (remember that current is conserved!). The amount of current in the circuit is determined by the potential difference (or em f) of the battery and the equivalent resistance, Req, of the circuit. We can therefore write Ohm's Law as DeltaV = IReq. Assume the batteries supply a potential difference of DeltaV = 3.0 V, and use the currents measured in circuits 3a, 3b, and 3c to determine the equivalent resistance in each circuit. Please show the calculation of each.
R1 = 150 ohm, R2 = 230 ohm R3 = 270 ohms (don't believe question should need these but providing anyways)
Current Measured
Current through R1 in 3a (Only resistor 1) Ir1= 0.01 amp
Current through R1 in 3b (Resistor 1 and 2) Ir1= 0.0032 amp
Current through R1 in 3c (Resistor 1, 2 and 3) Ir1 = 0.002 amp
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
