In a certain school district, it was observed that 32% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 84 out of 218 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the α=0.05α=0.05 level of significance. What is the hypothesized population proportion for this test? p=p= Choose the correct pair of hypotheses for this situation: (A) (B) (C) H0:p=0.32H0:p=0.32 Ha:p<0.32Ha:p<0.32 H0:p=0.32H0:p=0.32 Ha:p≠0.32Ha:p≠0.32 H0:p=0.32H0:p=0.32 Ha:p>0.32Ha:p>0.32 (D) (E) (F) H0:p=0.385H0:p=0.385 Ha:p<0.385Ha:p<0.385 H0:p=0.385H0:p=0.385 Ha:p≠0.385Ha:p≠0.385 H0:p=0.385H0:p=0.385 Ha:p>0.385Ha:p>0.385 (A) (B) (C) (D) (E) (F) Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion? z=z= (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value =
In a certain school district, it was observed that 32% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 84 out of 218 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the α=0.05α=0.05 level of significance.
What is the hypothesized population proportion for this test?
p=p=
Choose the correct pair of hypotheses for this situation:
(A) | (B) | (C) | H0:p=0.32H0:p=0.32 Ha:p<0.32Ha:p<0.32 |
H0:p=0.32H0:p=0.32 Ha:p≠0.32Ha:p≠0.32 |
H0:p=0.32H0:p=0.32 Ha:p>0.32Ha:p>0.32 |
(D) | (E) | (F) | H0:p=0.385H0:p=0.385 Ha:p<0.385Ha:p<0.385 |
H0:p=0.385H0:p=0.385 Ha:p≠0.385Ha:p≠0.385 |
H0:p=0.385H0:p=0.385 Ha:p>0.385Ha:p>0.385 |
---|
Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion?
z=z=
(Report answer as a decimal accurate to 3 decimal places.)
You are now ready to calculate the P-value for this sample.
P-value =
Trending now
This is a popular solution!
Step by step
Solved in 5 steps