In a biprism experiment the distance between the 1st and 11th bright fringes formed by light of wavelength λ is 1.8 × 10³ m. 2 If the light is replaced by one of wavelength 2 find the distance between 1st and 16th bright fringe.
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A: given: index of refraction (n) = 1.3 thickness (t)= 325nmformula:λ= 2nt / m+ 1/2λ= 2(1.3)(325)nm /…
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A: To find-Wavelength of light (λ2)=?Given-(X13-X4)λ1=X15-X5λ2λ1=6000 A0λ1=6×10-7 m
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A: in this question we use path difference equation for L>>>y .
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A: This problem can be solved using the formula for double slit interference.
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A: Slit separation, d = 131 μmθ = 0.67°Order, n = 3
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A: Given that--- Frequency = 453 THz refraction index of oil = 1.47 refraction index of water = 1.33…
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A: wavelength of water waves (λ) = 3 mdistance between row of posts (d) = 5 m order (n) = 1
Q: The Michelson interferometer can be used to measure the index of refraction of a gas by placing an…
A: Wavelength of light = Length of tube = L = 5.40 cm Fringe shift (number) = N = 168
Q: A bubble is formed by a soap film with index of refraction n=1.3 and a thickness of 325nm. When…
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A: Given, The angle of the prism: A=60° Incident angle: i1=55° Refractive index for red light: μr=1.45…
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