In a balanced three-phase system, the source is a balanced Y with an abc phase sequence and a line voltage Vab = 2092 55°V. The load is a balanced Y in parallel with a balanced A. The phase impedance of the Y is 5+5j N/Þ and the phase impedance of the A is 3-9j N/Ø. The line impedance is 1.4+0.5j 2/P. Use the single phase equivalent circuit to calculate the line voltage at the load in the a-phase. Express your answer in volts to three significant figures. Enter your answer using angle notation. Express argument in degrees. • View Available Hint(s) AEo t vec ? VAB = 147.53/46.63 V

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In a balanced three-phase system, the source is a balanced Y with an abc phase sequence and a line voltage
Vab = 2092 55°V. The load is a balanced Y in parallel with a balanced A. The phase impedance of the Y is 5+5j N/Þ and
the phase impedance of the A is 3-9j N/Ø. The line impedance is 1.4+0.5j 2/P. Use the single phase equivalent circuit to
calculate the line voltage at the load in the a-phase.
Express your answer in volts to three significant figures. Enter your answer using angle notation. Express argument in
degrees.
• View Available Hint(s)
AEo t vec
?
VAB = 147.53/46.63
V
Transcribed Image Text:In a balanced three-phase system, the source is a balanced Y with an abc phase sequence and a line voltage Vab = 2092 55°V. The load is a balanced Y in parallel with a balanced A. The phase impedance of the Y is 5+5j N/Þ and the phase impedance of the A is 3-9j N/Ø. The line impedance is 1.4+0.5j 2/P. Use the single phase equivalent circuit to calculate the line voltage at the load in the a-phase. Express your answer in volts to three significant figures. Enter your answer using angle notation. Express argument in degrees. • View Available Hint(s) AEo t vec ? VAB = 147.53/46.63 V
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