In a 56.0-g aqueous solution of methanol, CH,O, the mole fraction of methanol is 0.280. What is the mass of each component? mass of CH,0: g CH,0 mass of water: gH,0
In a 56.0-g aqueous solution of methanol, CH,O, the mole fraction of methanol is 0.280. What is the mass of each component? mass of CH,0: g CH,0 mass of water: gH,0
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:In a 56.0-g aqueous solution of methanol, CH, O, the mole fraction of methanol is 0.280.
What is the mass of each component?
mass of CH0 :
&CH,O
mass of water:
g H,0
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Expert Solution
Step 1
Molar mass of methanol = 32.04 g / mol
Let mass of methanol present = a g
Mass of water = (56 - a) g
Molar mass of water = 18 g / mol
Moles of methanol present = a / 32.04
Moles of water = (56 - a) / 18
Total number of moles = (a / 32.04) + {(56 - a) / 18} = (1794.24 - 14.04a) / 576.72
Therefore, (a / 32.04) / [(1794.24 - 14.04a) / 576.72] = 0.280
or, 576.72 a = 16096.49 - 125.96 a
or, 702.68 a = 16096.49
or, a = 22.9 g
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