In a 4.00 L pressure cooker, water is brought to a boil. If the final temperature is 115.0 °C at 3.20 atm, What quantity in moles of steam are in the cooker?

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### Problem Statement:

In a 4.00 L pressure cooker, water is brought to a boil. If the final temperature is 115.0 °C at 3.20 atm, what quantity in moles of steam are in the cooker?

### Solution Approach:

To find the quantity of steam in moles, we can use the Ideal Gas Law, which is stated as follows:

\[ PV = nRT \]

Where:
- \( P \) is the pressure in atm,
- \( V \) is the volume in liters,
- \( n \) is the number of moles,
- \( R \) is the ideal gas constant (\( 0.0821 \, \text{L} \cdot \text{atm} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \)),
- \( T \) is the temperature in Kelvin.

### Conversion Steps:

1. **Convert Temperature to Kelvin:**
   \[ T(K) = 115.0 \, °C + 273.15 = 388.15 \, K \]

2. **Rearrange the Ideal Gas Law to solve for \( n \):**
   \[ n = \frac{PV}{RT} \]

3. **Substitute the given values into the equation:**
   \[ n = \frac{(3.20 \, \text{atm})(4.00 \, \text{L})}{(0.0821 \, \text{L} \cdot \text{atm} \cdot \text{mol}^{-1} \cdot \text{K}^{-1})(388.15 \, K)} \]

### Calculation:

\[ n = \frac{12.8 \, \text{L} \cdot \text{atm}}{31.8670 \, \text{L} \cdot \text{atm} \cdot \text{mol}^{-1}} \]
\[ n \approx 0.402 \, \text{mol} \]

### Conclusion:

The quantity of steam in the pressure cooker is approximately **0.402 moles**.

### Notes:

- Ensure all units are consistent when using the Ideal Gas Law.
- The Ideal Gas Law assumes an ideal behavior of gases, which is a good approximation under many conditions but may deviate under extreme conditions.
Transcribed Image Text:### Problem Statement: In a 4.00 L pressure cooker, water is brought to a boil. If the final temperature is 115.0 °C at 3.20 atm, what quantity in moles of steam are in the cooker? ### Solution Approach: To find the quantity of steam in moles, we can use the Ideal Gas Law, which is stated as follows: \[ PV = nRT \] Where: - \( P \) is the pressure in atm, - \( V \) is the volume in liters, - \( n \) is the number of moles, - \( R \) is the ideal gas constant (\( 0.0821 \, \text{L} \cdot \text{atm} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \)), - \( T \) is the temperature in Kelvin. ### Conversion Steps: 1. **Convert Temperature to Kelvin:** \[ T(K) = 115.0 \, °C + 273.15 = 388.15 \, K \] 2. **Rearrange the Ideal Gas Law to solve for \( n \):** \[ n = \frac{PV}{RT} \] 3. **Substitute the given values into the equation:** \[ n = \frac{(3.20 \, \text{atm})(4.00 \, \text{L})}{(0.0821 \, \text{L} \cdot \text{atm} \cdot \text{mol}^{-1} \cdot \text{K}^{-1})(388.15 \, K)} \] ### Calculation: \[ n = \frac{12.8 \, \text{L} \cdot \text{atm}}{31.8670 \, \text{L} \cdot \text{atm} \cdot \text{mol}^{-1}} \] \[ n \approx 0.402 \, \text{mol} \] ### Conclusion: The quantity of steam in the pressure cooker is approximately **0.402 moles**. ### Notes: - Ensure all units are consistent when using the Ideal Gas Law. - The Ideal Gas Law assumes an ideal behavior of gases, which is a good approximation under many conditions but may deviate under extreme conditions.
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