A rigid gas cylinder at 25.0 °C is pressured with 1.29 atm of an ideal gas. If the temperature is then increased to 67.4°C, what will the pressure in the cylinder become? State your answer in atm (without units).

Q: The temperature of a sample of gas in a steel tank at 30.0 kPa is increased from -100.0°C to 25.0…

A:

Q: For many purposes we can treat methane (CH,) as an ideal gas at temperatures above its boiling point…

A: Given that: Initial temperature (T1) = 12.0°C = 285 K Final temperature (T2) = -11.0°C = 262 K…

Q: A cylinder containing 15.0 L of helium gas at a pressure of 165 atm is to be used to fill party…

A: Consider the given information is as follows; Volume of the cylinder = 15.0 L Volume of the balloon…

Q: (CH4) as an ideal gas at temperatures above its boiling point of -161. °C. Suppose the temperature…

A: The Ideal Gas equation is given by,PV = nRTwhere,P= Pressure in atmV = Volume in LT = Temperature in…

Q: Imagine an ideal gas in a cylinder with a piston starting at a pressure of 1.00 atm and a volume of…

A: Given: Initial pressure (P1) is 1.00 atm Initial volume (V1) is 10.0 L Initial temperature (T1) is…

Q: For many purposes we can treat ammonia (NH,) as an ideal gas at temperatures above its boiling point…

A: Ideal gas equation is PV = nRT,we will use this equation.

Q: For many purposes we can treat butane (C,H10) as an ideal gas at temperatures above its boiling…

A: Two questions based on gas law, which are to be accomplished.

Q: A sample of a gas was confined in a cylinder fitted with a movable piston. At 20.0 °C, the gas…

A: T1=20.0°C=(20.0+273.15)K=293.15K V1=7.104L P1=1.128 atm T2=99.9°C=(99.9+273.15)K=373.05K P2=5.0 14…

Q: For many purposes we can treat propane (C₂Hg) as an ideal gas at temperatures above its boiling…

A:

Q: For many purposes we can treat ammonia (NH3) as an ideal gas at temperatures above its boiling point…

A:

Q: For many purposes we can treat propane (C3Hg). as an ideal gas at temperatures above its boiling…

A: Ideal gas equation is  PV = nRT  Where P is pressure V is volume n is no. Of moles  R is gas…

Q: ired to decrease the volume of the gas sample to 7.44 L, p 0.540 atm, the temperature of the gas…

A: Initial Volume = 9.40 L Initial Temperature =53 °c = 326 K Initial pressure = 0.440 atm Final…

Q: For many purposes we can treat propane  C3H8 as an ideal gas at temperatures above its boiling…

A: (a)

Q: For many purposes we can treat methane (CH,) as an ideal gas at temperatures above its boiling point…

A:

Q: For many purposes we can treat nitrogen (N₂) as an ideal gas at temperatures above its boiling point…

A: The Ideal Gas equation is given by,PV = nRTwhere,P= Pressure in atmV = Volume in LT = Temperature in…

Q: (a) A tank contains one mole of oxygen gas at a pressure of 6.30 atm and a temperature of 29.5°C.…

A: a) Given Conditions are as follows: Initial pressure, P1 = 6.30 atm Initial temperature, T1 = 29.5˚C…

Q: For many purposes we can treat methane (CH₂) as an ideal gas at temperatures above its boiling point…

A: Answer:When number of moles of a gas are constant and R is universal gas constant, so,  must be…

Q: A gas sample containing 0.6838 moles is trapped in a chamber with a volume of 7.557 liters.  If the…

A: n = 0.6838 molV = 7.557 LT = 298.17 K

Q: A cylinder contains 12.8 L of air at a total pressure of 45.0 psi and a temperature of 30 ∘C. How…

A: Given: The volume of air in the cylinder = 12.8 L The total pressure = 45.0 psi Temperature = 30 ∘C…

Q: For many purposes we can treat nitrogen (N,) as an ideal gas at temperatures above its boiling point…

A: According to ideal gas law, PV = nRT where P = pressure V = volume n = moles R = gas constant =…

Q: For many purposes we can treat propane (C3H8) as an ideal gas at temperatures above its boiling…

A: Given: The initial pressure = 4.2 atm The initial temperature = -22.0 oC The final temperature =…

Q: For many purposes we can treat ammonia (NH,) as an ideal gas at temperatures above its boiling point…

A:

Q: For many purposes we can treat methane (CH) as an ideal gas at temperatures above its boiling point…

A:

Q: 37. Mixture of helium gas and oxygen gas are used in the "air" tank of underwater divers for deep…

A: Given: The given mass of O2=0.86 g. The mass of He=2.1 g. The molar mass of O2=32 g/mol. The molar…

Q: For many purposes we can treat propane (C,H) as an ideal gas at temperatures above its boiling point…

A: Here we use ideal gas equation because the gas is above -42 degree celcius.

Q: For many purposes we can treat methane (CH,) as an Ideal gas at temperatures above Its bolling polnt…

A: Given: The temperature of a methane gas sample is raised from -21.0 oC to 13.0 oC. The initial…

Q: For many purposes we can treat propane (C,H) as an ideal gas at temperatures above its boiling point…

A: Initial temperature, pressure, volume of the propane gas, whose final pressure is to be determined…

Q: If the average kinetic energy of the molecules in an ideal gas initially at 28°C doubles, what is…

A: Initial Temperature = 28°C or 301 K

Q: a type of oxide nitrogen gas was produced from an experiment. the gas has a mass of 3.633g and…

A: Recall the following relation to calculate molar mass of the gas        PV=nRT       PV=wMRT…

Q: For many purposes we can treat propane (CH) as an ideal gas at temperatures above its boiling point…

A: Given,the temperature of propane ( C3H8 ) gas is lowered from 21.0 oC to -24.0 oCInitial pressure of…

Q: For many purposes we can treat propane (C, Hg) as an ideal gas at temperatures above its boiling…

A: Pressure can be calculated as :-

Q: For many purposes we can treat propane (C₂H₂) as an ideal gas at temperatures above its boiling…

A: We can solve this problem by using ideal gas equation.

Q: Under what conditions does a gas become non-ideal? What is responsible for this behavior?Under what…

A: Under what conditions does a gas become non-ideal? What is responsible for this behavior?

Q: For many purposes we can treat ammonia (NH,) as an ideal gas at temperatures above its boiling point…

A: For an ideal gas pressure is inversely proportional to volume of the gas .

Q: For many purposes we can treat propane (C,H3) as an ideal gas at temperatures above its boiling…

A:

Kinetic-Theory of Gases

Kinetic theory of gases is the model or method which was developed in the 19th century by Maxwell and Boltzmann. This is possible as the interatomic force which is of short-range forces that are important for solids and liquids can be neglected for gases. This theory or gas law gives a molecular interpretation of the pressure and temperature of a gas and is consistent with gas laws and Avogadro’s hypothesis. This theory is very helpful to correctly explain the specific heat capacities of many gases, kinetic energy and it also explains the transport qualities such as viscosity, thermal conductivity, and diffusion with molecular parameters. As stated in the kinetic-molecular theory, the temperature of a substance or gas particle is related to the average kinetic energy of the particles of that substance. When a substance is heated, some of the absorbed energy is stored within the particles, while some of the energy increases the motion of the particles, called average kinetic energy.