In a 280-turn automobile alternator, the magnetic flux in each turn is R = 2.50 × 104 cos wt, where , is in webers, w is the angular speed of the alternator, and t is in seconds. The alternator is geared to rotate two times for each engine revolution. The engine is running at an angular speed of 1.00 x 10° rev/min. (a) Determine the induced emf in the alternator as a function of time. (Assume Ɛ is in V.) E =| (21.98V)sin (314t) (b) Determine the maximum emf in the alternator. 21.98 X V

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In a 280-turn automobile alternator, the magnetic flux in each turn is ¢. = 2.50 x 10-4 cos wt, where , is in webers, w is the angular speed of the alternator, and t is in seconds. The
alternator is geared to rotate two times for each engine revolution. The engine is running at an angular speed of 1.00 x 10° rev/min.
(a) Determine the induced emf in the alternator as a function of time. (Assume E is in V.)
E = (21.98V)sin(314t)
(b) Determine the maximum emf in the alternator.
21.98
X V
Transcribed Image Text:In a 280-turn automobile alternator, the magnetic flux in each turn is ¢. = 2.50 x 10-4 cos wt, where , is in webers, w is the angular speed of the alternator, and t is in seconds. The alternator is geared to rotate two times for each engine revolution. The engine is running at an angular speed of 1.00 x 10° rev/min. (a) Determine the induced emf in the alternator as a function of time. (Assume E is in V.) E = (21.98V)sin(314t) (b) Determine the maximum emf in the alternator. 21.98 X V
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