In 2nd order reaction 2OH →→ H2O + O k = 1.47 x 1010 M-1 s-1. There is an initial OH concentration of [OH]0 = 1.88×10−4M. which takes 3.77 x 10^-7s for the oxygen concetration to decrease to 6.0997×10−5M. b) At time 3.77 x 10^-7s, what will the oxygen concetration be?
In 2nd order reaction 2OH →→ H2O + O k = 1.47 x 1010 M-1 s-1. There is an initial OH concentration of [OH]0 = 1.88×10−4M. which takes 3.77 x 10^-7s for the oxygen concetration to decrease to 6.0997×10−5M. b) At time 3.77 x 10^-7s, what will the oxygen concetration be?
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In 2nd order reaction 2OH →→ H2O + O k = 1.47 x 1010 M-1 s-1. There is an initial OH concentration of [OH]0 = 1.88×10−4M. which takes 3.77 x 10^-7s for the oxygen concetration to decrease to 6.0997×10−5M.
b) At time 3.77 x 10^-7s, what will the oxygen concetration be?
Expert Solution
Step 1
Provided 2nd order reaction
2OH → H2O + O
Rate constant, k = 1.47 x 1010 M-1 s-1
Initial concentration, [OH]0 = 1.88×10−4M
Time, t=3.77 x 10-7 s
Final concentration. [OH]=?
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