In 2003, Major League Baseball took steps to speed up the paly of baseball games and make games a more consistent duration. In a sample of 46 games in 2002, the average duration of a game was 2 hours and 58 minutes with a standard deviation of 37 minutes. A similar survey in 2003 of 54 games found that the average duration was 2 hours and 40 minutes with a standard deviation of 22 minutes. When testing the hypothesis (at the 5% level of significance) that the variance has been reduced, what is the test statistic? (please round your answer to 2 decimal places)
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: Claim: Insurance Company A claims that its customers pay less for car insurance, on average, than…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with…
A: From the provided information, Sample size (n) = 64 Sample mean (x̅) = 0.9 Sample standard deviation…
Q: An industrial plant wants to determine which of two types of fuel, electric or gas, is more cost…
A: Given data 1- denotes plants using electricity 2 – denotes plants using gas Formulation of…
Q: Two ride-sharing companies are competing for business in a large city. To help customers compare the…
A: The true means' difference CI is (x¯1-x¯2)±ts12n1+s22n2where x¯1 and x¯2=means of both sampless1…
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: Answer Given Mean [x1] =151 Mean [x2] =158 Standard deviation [s1] =19 Standard deviation [s2] =14…
Q: Dougall compared the resting heart rate of average healthy citizens and soldiers suffering from…
A: Given that,Dougall compared the resting heart rate of average healthy citizens and soldiers…
Q: An article presents a study of health outcomes in women with symptoms of heart disease. In a sample…
A:
Q: According to a research study, American teenagers watched 14.8 hours of television per week last…
A: Given a hypothesis test to check the mean amount of time american teenagers watch television per…
Q: An industrial plant wants to determine which of two types of fuel, electric or gas, is more cost…
A: There are two independent samples which are electricity and gas. Both samples follows normal…
Q: A researcher claims that felons convicted of tax fraud spend less than 18 months in jail, on…
A: The given sample size is 10, sample mean is 13.8, sample standard deviation is 3.3, and population…
Q: Are low-fat diets or low-carb diets more effective for weight loss? This question was addressed by a…
A: Given that, for a low-carbohydrate diet n1=77, x1=4.7 kg, s1=7.2 kg For a low-fat diet, n2=79,…
Q: A parent interest group is looking at whether birth order affects scores on the ACT test. It was…
A: We want to tell you alternative hypothesis
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: Company A Sample size, n1=11 Sample mean, x¯1=150 Sample sd, s1=12 Company B Sample size, n2=13…
Q: According to a technician's study, male coworkers had 11.4 hours per month of overtime last year, on…
A: Given that, μ = 11.4x = 10.7s= 1.5 n = 15 H0: μ = 11.4 Vs Ha: μ ≠ 11.4 which is two tailed test.…
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The question is about hypothesis testing.Given :Randomly selected no. of people who buy insurance…
Q: In a test of the effectiveness of garlic for lowering cholesterol,64 subjects were treated with raw…
A: Given: n = 64 d = 0.7 sd = 1.51 α = 0.01 Formula Used: Test-statistic-t = d-μdsdn
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: Company A:Sample size Sample mean Sample standard deviation Company B:Sample size Sample mean Sample…
Q: Community college instructors' salaries in one state are very low, so low that educators in that…
A: We have given that the hypothetical mean 51809, sample mean 45068, sample size 33 and standard…
Q: Step 3 of 3: Draw a conclusion and interpret the decision. Answer Tables E Keypad Keyboard Shortcuts…
A: Given Data : For first born children x̄1 = 24.4 σ1 = 1.5 n1 = 225 For…
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The objective of this question is to state the null and alternative hypotheses for a statistical…
Q: parenting magazine reports that the average amount of wireless data used by teenagers each month is…
A: To test Ella's claim, we can perform a one-sample t-test. Here are the steps involved: Step 1:…
Q: A parent interest group is looking at whether birth order affects scores on the ACT test. It was…
A:
Q: In 2003, Major League Baseball took steps to speed up the paly of baseball games and make games a…
A: The standard deviations s1 and s2 are 34 and 20, respectively.
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: From the provided information,
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The question is about hypothesis testing.Given :Randomly selected no. of people who buy insurance…
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The hypothesis is a statement of claim. There are two types of hypotheses. The null hypothesis is…
Q: According to a research study, American teenagers watched 14.8 hours of television per week last…
A: a.Let µ be the true mean amount of time per week each teenager watched television.Let x bar be the…
Q: In a sample of 50 business trips taken by employees in the HR department, a company finds that the…
A:
Q: nsurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The sample size for company A is 15, the mean is $150 and the standard deviation is $14.The sample…
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The objective of this question is to formulate the null and alternative hypotheses for a statistical…
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: n1=15,x1¯=150,s1=14n2=6,x2¯=157,s2=11
Q: In 2003, Major League Baseball took steps to speed up the paly of baseball games and make games a…
A:
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The insurance Company A claims that its customers pay less for car insurance, on average, than…
Q: Insurance Company A claims that its customers pay less for car insurance, on average than customers…
A: Formula : test statistic for equal variance t test is
Q: Researchers conducted an experiment to test the effects of alcohol. Errors were recorded in a test…
A:
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: For the people who buy insurance from Company A,Sample size, Mean, Sd, For the people who buy…
Q: players, good hip range of motion results in improved performance and decreased body stress. A…
A: Given Data : For Sample 1 x̄1 = 75.8 s1 = 5.6 n1 = 40 For Sample 2…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with…
A: State the hypotheses. That is, there is no evidence that with the garlic treatment, the mean change…
Q: In its 2016 Auto Reliability Survey, Consumer Reports asked subscribers to report their maintenance…
A: a. Let σ12 is defined as the population variance of 4 year old automobiles, and σ22 is defined as…
Q: According to a research study, college students spent 24.2 hours doing homework per week last year,…
A: According to a research study, college students spent 24.2 hours doing homework per week last year,…
Q: In attempting to improve student services, a college investigates its registration process and finds…
A: If x¯1 and x¯2 are the means of two independent sample of size n1 and n2 with sample deviation s1…
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The objective of this question is to compute the value of the test statistic for the claim that…
Q: According to Management Accounting, salary figures for certified management accountants (CMAs) who…
A: Given that : A certiecd mangwmwnr acjeqk ccountansts ) who are in the field less than a yesr which…
Q: Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to…
A: Use the Two sample independent t test Sample Mean 36.41 Standard Deviation (S1)…
Q: Average adult Americans are about one inch taller but nearly a whopping 25 pounds heavier than they…
A: According to the given information in this question We need to apply z test for one population mean
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: The objective of this question is to formulate the null and alternative hypotheses for a statistical…
Q: Community college instructors' salaries in one state are very low, so low that educators in that…
A: Given, Population mean, μ = $45,661 Sample mean, x = $43,024 Sample standard deviation, σ = $13,132…
In 2003, Major League Baseball took steps to speed up the paly of baseball games and make games a more consistent duration. In a sample of 46 games in 2002, the average duration of a game was 2 hours and 58 minutes with a standard deviation of 37 minutes. A similar survey in 2003 of 54 games found that the average duration was 2 hours and 40 minutes with a standard deviation of 22 minutes. When testing the hypothesis (at the 5% level of significance) that the variance has been reduced, what is the test statistic? (please round your answer to 2 decimal places)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
- Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenInsurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 15 people who buy insurance from Company A, the mean cost is $154 per month with a standard deviation of $13. For 11 randomly selected customers of Company B, you find that they pay a mean of $159 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.02 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 12people who buy insurance from Company A, the mean cost is $153 per month with a standard deviation of $16. For 15 randomly selected customers of Company B, you find that they pay a mean of $160 per month with a standard deviation of $10. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha: μ1_____μ2 Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places Step 3 of…
- An industrial plant wants to determine which of two types of fuel, electric or gas, is more cost efficient (measured in cost per unit of energy). Independent random samples were taken of plants using electricity and plants using gas. These samples consisted of 14 plants using electricity, which had a mean cost per unit of $55.06 and standard deviation of $8.25, and 12 plants using gas, which had a mean of $57.80 and standard deviation of $7.81. Assume that the populations of costs per unit are normally distributed for each type of fuel, and assume that the variances of these populations are equal. Can we conclude, at the 0.10 level of significance, that μ₁, the mean cost per unit for plants using electricity, differs from μ₂, the mean cost per unit for plants using gas? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of…The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. It is an attractive alternative to getting an MBA for students wanting a career in investment. A student of finance is curious to know if a CFA designation is a more lucrative option than an MBA. He collects data on 38 recent CFAs with a mean salary of $138,000 and a standard deviation of $34,000. A sample of 80 MBAs results in a mean salary of $130,000 with a standard deviation of $46,000.a) Specify the hypotheses to test whether a CFA designation is more lucrative than an MBA.b) Calculate the value of the test statistic and the p-value. Do not assume that the population variances are equal.c) At the 5% significance level, is a CFA designation more lucrative than an MBA?The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. It is an attractive alternative to getting an MBA for students wanting a career in investment. A student of finance is curious to know if a CFA designation is a more lucrative option than an MBA. He collects data on 36 recent CFAS with a mean salary of $145,000 and a standard deviation of $36,000. A sample of 47 MBAS results in a mean salary of $135,000 with a standard deviation of $24,000. Assume that H, is the population mean for individuals with a CFA designation and u, is the population mean of individuals with MBAS. (You may find it useful to reference the appropriate table: z table or t table) a. Set up the hypotheses to test if a CFA designation is more lucrative than an MBA at the 10% significance level. O Họ: 41- H2 = 0; HA: H1 - H2# 0 O Ho: 1-4220; HA H1 - 4200 b-1. Calculate the value of the test statistic. Do not assume that the population variances are…
- Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 1313 people who buy insurance from Company A, the mean cost is $151$151 per month with a standard deviation of $16$16. For 99 randomly selected customers of Company B, you find that they pay a mean of $158$158 per month with a standard deviation of $19$19. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.050.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.In its 2016 Auto Reliability Survey, Consumer Reports asked subscribers to report their maintenance and repair costs. Most individuals are aware of the fact that the average annual repair cost for an automobile depends on the age of the automobile. A researcher is interested in finding out whether the variance of the annual repair costs also increases with the age of the automobile. A sample of 26 automobiles 4 years old showed a sample standard deviation for annual repair costs of $190 and a sample of 24 automobiles 2 years old showed a sample standard deviation for annual repair costs of $100. a. State the null and alternative versions of the research hypothesis that the variance in annual repair costs is larger for the older automobiles. Let 4 year old automobiles be represented by population 1. 0² Ho o less than or equal to H₁: o greater than b. At a 0.01 level of significance, what is your conclusion? Calculate the value of the test statistic (to 2 décimals). Ⓡ The p-value is less…In its 2016 Auto Reliability Survey, Consumer Reports asked subscribers to report their maintenance and repair costs. Most individuals are aware of the fact that the average annual repair cost for an automobile depends on the age of the automobile. A researcher is interested in finding out whether the variance of the annual repair costs also increases with the age of the automobile. A sample of 26 automobiles 4 years old showed a sample standard deviation for annual repair costs of $210 and a sample of 25 automobiles 2 years old showed a sample standard deviation for annual repair costs of $100. (a) State the null and alternative versions of the research hypothesis that the variance in annual repair costs is larger for the older automobiles. (b) At a 0.01 level of significance, what is your conclusion? Find the value of the test statistic. (c) Find the p-value. (Round your answer to four decimal places.) p-value = (d) State your conclusion: A) Reject H0. We can conclude that…
- An industrial plant wants to determine which of two types of fuel, electric or gas, is more cost efficient (measured in cost per unit of energy). Independent random samples were taken of plants using electricity and plants using gas. These samples consisted of 7 plants using electricity, which had a mean cost per unit of $64.13 and standard deviation of $8.32, and 12 plants using gas, which had a mean of $60.30 and standard deviation of $8.52. Assume that the populations of costs per unit are normally distributed for each type of fuel, and assume that the variances of these populations are equal. Can we conclude, at the 0.10 level of significance, that u,, the mean cost per unit for plants using electricity, differs from u, the mean cost per unit for plants using gas? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)…In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.8 and a standard deviation of 2.14. Use a 0.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.…As an owner of a business, having a consistent level of sales is important. Prior to the recession that started in 2007, the standard deviation of the sales of a local business was $506. In a sample of 29 weeks since the start of the recession, sales have averaged $6800 per week with a standard deviation of $785. When testing the hypothesis (at the 5% level of significance) that the variance is higher than it was pre-recession (so the null hypothesis is that the variance is less than 506 2 ). what is the critical value? (please round your answer to 2 decimal places)
