In 1897, the English physicist J. J. Thomson used crossed electric and magnetic fields to measure the charge to mass ratio of electrons. (A) Determine the ratio in Sl units. (B) Determine the charge to mass ratio of a proton. (C) In one experiment, electrons are accelerated to speed v by an electric field E, and are then deflected by a magnetic field B. For the parameters given below, calculate the radius of the circular arc in the magnetic field. electric field = 1.00 kV/cm; distance of the acceleration = 0.79 m; magnetic field = 0.06 T ] ✓

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Course Contents » Problem Set # 4 (due Wednes 9/... » The J. J. Thomson experiment
In 1897, the English physicist J. J. Thomson used
crossed electric and magnetic fields to measure the
charge to mass ratio of electrons. (A) Determine the
ratio in SI units. (B) Determine the charge to mass
ratio of a proton. (C) In one experiment, electrons are
accelerated to speed v by an electric field E, and are
then deflected by a magnetic field B. For the
parameters given below, calculate the radius of the
circular arc in the magnetic field.
electric field = 1.00 kV/cm; distance of the acceleration = 0.79 m; magnetic field = 0.06 T ]
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Transcribed Image Text:Course Contents » Problem Set # 4 (due Wednes 9/... » The J. J. Thomson experiment In 1897, the English physicist J. J. Thomson used crossed electric and magnetic fields to measure the charge to mass ratio of electrons. (A) Determine the ratio in SI units. (B) Determine the charge to mass ratio of a proton. (C) In one experiment, electrons are accelerated to speed v by an electric field E, and are then deflected by a magnetic field B. For the parameters given below, calculate the radius of the circular arc in the magnetic field. electric field = 1.00 kV/cm; distance of the acceleration = 0.79 m; magnetic field = 0.06 T ] Submit Answer Tries 0/12 Submit Answer Tries 0/12 Submit Answer Tries 0/12 Post Discussion ◄ Timer
Expert Solution
Step 1: Determine charge to mass ratio of electron and proton

Solution 

      Given data

Electric field E=1.0(kV)/(cm)=1.0×103×102Vm

Electric field E=1×105Vm

Distance d = 0.79 m

Magnitude field B = 0.06 T

Mass of electron me=9.11×1031kg

Mass of proton mp=1.673×1027kg

Charge on electron q=1.6×1019C

Determine the charge to mass ratio of electron and proton. 

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