Implement the following expression in assembly language: result = (val3 + val4) (vall - val2) (30*4)/55 Assume that result, vall, val2, val3 and val4 are 16-bit integer variables You need to implement the expression the way it is provided, you cannot do any reduction on the expression while implementing it. - Initialize vall with 134 (hexadecimal), va12 with 139 (hexadecimal), val3 with 67 (hexadecimal) and val4 with 47 (hexadecimal) -

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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**Implement the following expression in assembly language:**

```
result = (val3 + val4) - (val1 - val2) - (30*4)/55
```

- Assume that `result`, `val1`, `val2`, `val3` and `val4` are **16-bit integer variables**.
- You need to implement the expression the way it is provided; you cannot perform any reduction on the expression while implementing it.
- Initialize:
  - `val1` with 134 (hexadecimal),
  - `val2` with 139 (hexadecimal),
  - `val3` with 67 (hexadecimal),
  - `val4` with 47 (hexadecimal).

This snippet provides instructions for implementing a mathematical expression in assembly language, with emphasis on precise variable initialization and adherence to expression order.
Transcribed Image Text:**Implement the following expression in assembly language:** ``` result = (val3 + val4) - (val1 - val2) - (30*4)/55 ``` - Assume that `result`, `val1`, `val2`, `val3` and `val4` are **16-bit integer variables**. - You need to implement the expression the way it is provided; you cannot perform any reduction on the expression while implementing it. - Initialize: - `val1` with 134 (hexadecimal), - `val2` with 139 (hexadecimal), - `val3` with 67 (hexadecimal), - `val4` with 47 (hexadecimal). This snippet provides instructions for implementing a mathematical expression in assembly language, with emphasis on precise variable initialization and adherence to expression order.
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