Implement the divide-and-conquer O(n) time

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Implement the divide-and-conquer O(n) time algorithm
.ll T-Mobile
10:24 PM
E LeetCode
Given an array nums of size n, return the majority
element.
The majority element is the element that appears
more than [n / 2] times. You may assume that
the majority element always exists in the array.
Example 1:
Input: nums =
[3,2,3]
Output: 3
Example 2:
Input: nums
[2,2,1,1,1,2,2]
Output: 2
Constraints:
n
nums.length
1 <= n <= 5 * 104
• -231 <= nums[i] <= 231 - 1
A leetcode.com
Transcribed Image Text:.ll T-Mobile 10:24 PM E LeetCode Given an array nums of size n, return the majority element. The majority element is the element that appears more than [n / 2] times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3 Example 2: Input: nums [2,2,1,1,1,2,2] Output: 2 Constraints: n nums.length 1 <= n <= 5 * 104 • -231 <= nums[i] <= 231 - 1 A leetcode.com
.ll T-Mobile
10:25 PM
E LeetCode
C++
1 v class Solution {
public:
int
majorityElement(vector<int>& nums)
{
4
}
};
AA
A leetcode.com
Transcribed Image Text:.ll T-Mobile 10:25 PM E LeetCode C++ 1 v class Solution { public: int majorityElement(vector<int>& nums) { 4 } }; AA A leetcode.com
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