impedance of (10 + j 15) ohms is connected in parallel with an impedance of (6 – j8) ohms. The total current is 15 A. Calculate the total power?

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter23: Resistive-inductive-capacitive Series Circuits
Section: Chapter Questions
Problem 9RQ: What is the power factor of the circuit in Question 6?
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An impedance of (10 + j 15) ohms is connected in parallel with an impedance of (6 – j8) ohms. The total current is 15 A. Calculate the total power?
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