Imagine you are able to observe a 7.5 MeV electron in the lab. Using the equations relating to relativistic energy and momentum, answer the following questions. a. What is the total energy of the electron? E=KE+ mc² + 2×108 + 7.5X106 = 2.075 X 108 V b. What is the velocity of the electron? E mc² V2 с É" = (mcg)² + cp² -2.996×10 c. What is the momentum of the electron? E² - (m ² ²)² = 0.83 eVs/m C2 m²c41 E² 8 mls
Imagine you are able to observe a 7.5 MeV electron in the lab. Using the equations relating to relativistic energy and momentum, answer the following questions. a. What is the total energy of the electron? E=KE+ mc² + 2×108 + 7.5X106 = 2.075 X 108 V b. What is the velocity of the electron? E mc² V2 с É" = (mcg)² + cp² -2.996×10 c. What is the momentum of the electron? E² - (m ² ²)² = 0.83 eVs/m C2 m²c41 E² 8 mls
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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For part c), how come we cannot use the relativistic momentum equation where p = mv/(sqrt(1-v^2/c^2))? Since we've already solved for velocity in part b)?

Transcribed Image Text:Imagine you are able to observe a 7.5 MeV electron in the lab. Using the equations
relating to relativistic energy and momentum, answer the following questions.
a. What is the total energy of the electron?
E÷KE + mc² = 2×108 + 7.5X106 = 2.075 × 108 V
b. What is the velocity of the electron?
mc2
hon
V2
с
E² = [mc²)² + c²
P=E²-(mc²) ²
✓ =
C. What is the momentum of the electron?
C2
√ in
- 2.996×10
-0.83 eVs/m
m² cu
его
8
m/s
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