Imagine two DNA duplexes X and Y. According to calculations using the nearest neighbor method the two duplexes have the same standard enthalpy of helix formation, but the formation of duplex X results in a greater standard entropy loss than does the formation of duplex Y. Which of the following are likely to be correct:

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Question:
Imagine two DNA duplexes X and Y. According to calculations using the nearest
neighbor method the two duplexes have the same standard enthalpy of helix
formation, but the formation of duplex X results in a greater standard entropy loss
than does the formation of duplex Y.
Which of the following are likely to be correct:
Duplex X will have a higher melting temperature than duplex Y.
All other things being equal, the greater the loss of entropy upon the formation of
a duplex, the more unstable we would expect that duplex to be. As we saw in the
video (time stamp ~20:40), a graph of 1/Tm versus In(CT) is predicted to give a
straight line. The slope of this line should be a function of the standard enthalpy
of helix formation, while the intercept should be a function of both the standard
enthalpy and the standard entropy of helix formation.
Duplex X will have the same melting temperature as duplex Y.
Graphs of 1/Tm versus In(CT) for the two duplexes will be parallel.
Graphs of 1/Tm versus In(CT) for the two duplexes will converge at low CT.
Graphs of 1/Tm versus In(CT) for the two duplexes will be superimposable.
None of the above.
What is the correct answer? Please
explain
Transcribed Image Text:Question: Imagine two DNA duplexes X and Y. According to calculations using the nearest neighbor method the two duplexes have the same standard enthalpy of helix formation, but the formation of duplex X results in a greater standard entropy loss than does the formation of duplex Y. Which of the following are likely to be correct: Duplex X will have a higher melting temperature than duplex Y. All other things being equal, the greater the loss of entropy upon the formation of a duplex, the more unstable we would expect that duplex to be. As we saw in the video (time stamp ~20:40), a graph of 1/Tm versus In(CT) is predicted to give a straight line. The slope of this line should be a function of the standard enthalpy of helix formation, while the intercept should be a function of both the standard enthalpy and the standard entropy of helix formation. Duplex X will have the same melting temperature as duplex Y. Graphs of 1/Tm versus In(CT) for the two duplexes will be parallel. Graphs of 1/Tm versus In(CT) for the two duplexes will converge at low CT. Graphs of 1/Tm versus In(CT) for the two duplexes will be superimposable. None of the above. What is the correct answer? Please explain
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