Imagine that you ve been invited to try out a new hoversuit, and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 8.40 x 10^-6 C/m2. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. What is the strength of the electric field in the region above the charged sheet? (This is easy, since I m going to give you the formula, which is E = 2 pik Q/A, where k is the electrical constant and Q/A is the charge density.) O 4.27E+05 N/C 6.64E+05 N/C 4.74E+05 N/C 1.42E+05 N/C

Imagine that you ve been invited to try out a new hoversuit, and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 8.40 x 10^-6 C/m2. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. What is the strength of the electric field in the region above the charged sheet? (This is easy, since I m going to give you the formula, which is E = 2 pik Q/A, where k is the electrical constant and Q/A is the charge density.) O 4.27E+05 N/C 6.64E+05 N/C 4.74E+05 N/C 1.42E+05 N/C

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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10. Imagine that you ve been invited to try out a new hoversuit , and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density 4.72 x 10^-6 C and your mass including the suit 69.3 kg. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you.. Suppose that while you were hovering, someone threw you a rock of mass 7.9 kg, and that you caught it. What would now be your rate of acceleration toward the ground? 1.00 m/s^2 9.81 m/s^2 8.81 m/s^2 1.40 m/s^2
An electron is placed at rest in an electric field of 510 N/C. Which of the followings is the speed of the electron 47.0 ns after being released? ( e = 1,6 × 10-19C,e, = 8,85 × 10-12c²/N.m², mej= 9,11× 10-31kg, m, = 1,67 × 10-27kg) Your answer: O A)1.4 x 105 m/s O B) 0.8 x 106 m/s O ) 0.3 x 104 m/s O D) 2.6 x 106 m/s O E)4.2 x 106 m/s
Wanda has shrunk Timmy down to a very small size so that he can study for his science test. He observes a charge of -4.255x10^-6C. that starts at rest in a region of constant, uniform electric field. Assume gravitational effects are negligible. At a time of 12.45s after the charge starts from rest, Wanda measures that the charge has a kinetic energy of 2.996x10^-6J. What would be the potential difference, in volts, the charge will move through after 8.310s?
Imagine that you’ve been invited to try out a new hoversuit , and here's how it works: Someone has setup a large flat sheet, many kilometers across, somewhere on the Earth, and they’ve charged the sheetup to a uniform charge density of 3.92 x 10^-6 C. You are issued a special suit that you wear, and it hascontrols on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative,that you might want. The idea is that you can control the amount of electrical repulsion (or attraction)between the suit and the charged sheet below you. Suppose your mass (including the suit) is 81.2 kg.How much charge must you give the suit if you want to fall up , that is, accelerate upward at the samerate that objects normally accelerate downward due to Earth s gravity?7.19E-03 C2.16E-03 C1.01E-02 C1.15E-02C
Imagine that you’ve been invited to try out a new hoversuit , and here's how it works: Someonehas set up a large flat sheet, many kilometers across, somewhere on the Earth, and they’vecharged the sheet up to a uniform charge density of 7.63 x 10^-6 C. You are issued a special suitthat you wear, and it has controls on it which allow you to charge the suit up to any number ofCoulombs (C), positive or negative, that you might want. The idea is that you can control theamount of electrical repulsion (or attraction) between the suit and the charged sheet belowyou. Suppose your mass (including the suit) is 62.8 kg. How much charge must you give the suitif you want to be able to just hover stationary above the charged sheet?1.43E-03 C4.29E-04 C2.15E-03 C2.29E-03 C
9. Imagine that you ve been invited to try out a new hoversuit , and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 8.52 x 10^-6 C, and your mass including the suit is 87.0 kg. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. How much charge must you give the suit if you want to fall down toward the sheet, but at the same rate as if you were on the Moon (remembering that the gravitational acceleration on the Moon is 1/6 what it is on Earth)? 2.07E-03 C 2.37E-03 C 2.66E-03 C 1.48E-03 C
Consider an object of mass 41.8 kg. Now imagine taking all the protons out of the object and stuffing them into a box. Also take all the electrons out of the object and stuff them in a second box. How much charge is contained in the box with all the protons? 8.00E+09 C 1.00E+09 C 2.00E+09 C 4.00E+09 C
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MY N An electron is to be accelerated in a uniform electric field having a strength of 1.90 x 106 v/m. (a) What energy in kev is given to the electron if it is accelerated through 0.790 m? kev (b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV (as in the Stanford Linear Accelerator, which is actually smaller than this)? km Additional Materials
Consider a polar molecule such as water, which has an electrical dipole moment of 6×10-30 Cm. Suppose we place such a molecule in an external electric field of 3.5×10-6 N/C. What is the difference in potential energy between the dipole moment being parallel to and anti-parallel to the electric field?
Two very small spheres are initially neutral and separated by a distance of 0.50 m. Suppose that 3.0 x 1013 electrons are removed from one sphere and placed on the other. (a.) Find the magnitude of its charge. (b.) What is the magnitude of the electrostatic force that acts on each sphere? (c.) Is the force attractive or repulsive? Why?
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