Imagine a satellite (Pioneer 10) in an orbit around Ganymede (Jupiter's moon).You want to generate electricity by attaching a conducting cable 10km long. Ifthe speed of the satellite is 7 km/s and the magnetic field of Ganymede is 60 nThow much emf will be generated? (Hint1: assume that magnetic field isperpendicular to the plane which contains the cable. Hint2: you can think of it asmotional emf) Is it possible to produce electricity this way forever? Explain youranswer.

Given: The length of the conducting cable is, l =10 km=104 m. The speed of the satellite is, v =7…

Answered: Imagine a satellite (Pioneer 10) in an…

Similar questions

The following video shows a magnetometer recording the magnetic field of the Earth. How would you estimate uncertainty in the total magnetic field strength (seen at the top of the screen in white text)? Why would you select this uncertainty? O Recording Back Magnetometer O y=-54.25 Total Magnetic Field = 167.16 µT Magnetic Field vs Time X-151.98 Z=-43.6 -100 42 Time (s) Btotal Magnetic Field (µT)
A cyclotron uses a strong magnetic field to keep protons moving in circular orbits. A proton begins in a small-diameter orbit with a low speed, but a weak oscillating electric field gradually accelerates it to higher and higher speeds. This causes the orbit's diameter to slowly increase until the proton exits the machine from a large-diameter orbit. One commercial cyclotron uses a 1.2 TT magnetic field to accelerate protons to a final kinetic energy of 1.0×10−12J1.0×10−12J. What is the diameter of the largest orbit, just before the protons exit the cyclotron?
Q8.2
The answer is 3.5. What is the work for this problem?
The answers 0 and 7.0*10^-6 are incorrect; I have one more shot at this question. Please help.
A velocity selector is tuned to allow an electron with a speed of 280279 m/s through with no deflection. It used a magnetic field of 7.8 mT. What is the magnitude of the electric field (in V/m) being used?
You have learned that a charge moving in an magnetic field can experience a magnetic force. Remarkably, anytime that a charged particle moves that particle produces its own magnetic field! The image below of magnetic compasses forming a circle around a current-carrying wire demonstrates the shape of the magnetic field. The magnetic field lines forms concentric circles around that wire. The strength of the field decreases with increasing distance away from the wire. If the current in the wire is 1.15A, what is the magnitude of the magnitude of the magnetic field (in ?μT, or micro-Tesla) a distance of 0.88m away from the wire?
A device called a railgun uses the magnetic force on currents to launch projectiles at very high speeds. An idealized model of a railgun is illustrated in (Figure 1). A 1.2 V power supply is connected to two conducting rails. A segment of copper wire, in a region of uniform magnetic field, slides freely on the rails. The wire has a 0.85 mΩ resistance and a mass of 4.4 g . Ignore the resistance of the rails. The power supply is switched on. What is the magnitude of the force on the wire? What will be the wire's speed after it has slid a distance of 8.0 cm ?
Consider a long, horizontal Large Wire with current of 10 A running through it. We want to levitate a horizontal, thin, 0.50 m length of wire above it. If the thin wire has a mass of 10 grams, and a current of 300 mA, how far above the Large Wire will it hover (net force of zero) due to magnetic and gravitational forces? A. If the thin wire hovers above the Large Wire due to their magnetic fields, are their currents going the same direction, or opposite directions. Explain. B. Draw a diagram and label the directions of currents, and all other relevant quantities and vectors. C. Find the distance above the Large Wire the small thin wire will hover (net force of zero). D. Would your answers to parts A and C change if we wanted to find a distance below (rather than above) the Large Wire that the smaller thin wire could hover, due to their magnetic fields. Explain. Don't calculate any values but draw a new diagram and explain how this situation compares to the problem above.
A particle passes through a mass spectrometer as illustrated in the figure below. The electric field between the plates of the velocity selector has a magnitude of 8060 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.0920 T. In the deflection chamber the particle strikes a photographic plate 39.6 cm removed from its exit point after traveling in a semicircle. The diagram depicts a velocity selector. The plane of the page is filled with symmetrically arranged crosses labeled vector B0, in above a horizontal plate, and vector Bin below the horizontal plate. Below the horizontal plate, two vertical plates are placed parallel to each other in the right position of the field. The left plate is positively charged and the right plate is negatively charged. The electric field vector E points from the positive plate to the right toward the negative plate. A positively charged particle of charge q and velocity vector v pointing upward…