Imaginary Axis 0.1 Root Locus of G 0.05 о -0.05 -0.1 -2 -1.8 -1.0 -1.4 Real Axis gain = [0, 200] locus Х open loop poles ° zeros -1.2 -1
Imaginary Axis 0.1 Root Locus of G 0.05 о -0.05 -0.1 -2 -1.8 -1.0 -1.4 Real Axis gain = [0, 200] locus Х open loop poles ° zeros -1.2 -1
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
The root locus method consists of determining in the s-plane the desirable positions of the poles of a control system in order to achieve the desired performance. This graphical method is a powerful tool for analyzing and designing closed-loop (feedback) control systems. Below is a graph showing the application of the root locus method of any transfer function.
Regarding the graph, evaluate the following statements:
I. The open-loop pole is located at s = -2.
II. The open-loop zero is located at s = -1.
III. The root locus in the s plane comprises the interval of s \epsilon [-2 1].
What is stated in:
![Imaginary Axis
0.1
Root Locus of G
0.05
о
-0.05
-0.1
-2
-1.8
-1.0
-1.4
Real Axis gain = [0, 200]
locus
Х
open loop poles
°
zeros
-1.2
-1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feeb3c5de-d0fa-4e9a-a5ec-9929e7cae952%2F959aaf53-b71e-44b2-b95b-322f8118f9ab%2Fqt4m8b9_processed.png&w=3840&q=75)
Transcribed Image Text:Imaginary Axis
0.1
Root Locus of G
0.05
о
-0.05
-0.1
-2
-1.8
-1.0
-1.4
Real Axis gain = [0, 200]
locus
Х
open loop poles
°
zeros
-1.2
-1
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