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Im 1/2 Re -273 -1/4 n-1 17 yln] + 1 n-: 14 n-1 5 (3 n- 1) x[n] = u[n] 4) x[n] u[n-1] 9 (4, n-1 n-1 2) 지미 ((3) +(0))n-1 5) x[n] = G) u[n] + 1 EG u[n – 1] x[n] = + - 4 u[n- n-1 n-1 u[n - 1] 6) x=(3() -3() )비n-1] 3) x[n] = 6) x[끼] +

Im 1/2 Re -273 -1/4 n-1 17 yln] + 1 n-: 14 n-1 5 (3 n- 1) x[n] = u[n] 4) x[n] u[n-1] 9 (4, n-1 n-1 2) 지미 ((3) +(0))n-1 5) x[n] = G) u[n] + 1 EG u[n – 1] x[n] = + - 4 u[n- n-1 n-1 u[n - 1] 6) x=(3() -3() )비n-1] 3) x[n] = 6) x[끼] +

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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It is computed to the input sign x[n] of the causal system given the pole-zero distribution. accordingly, in which option is the input sign x[n] given correctly?

 

Im 1/2 Re -273 -1/4 n-1 17 yln] + n-: n-1 n- = (-G) +SG) 1) x[n] = 1/ + u[n] 5 (3 u[n 1] 4) x[n] 9 (4, n-1 n-1 2) 지미 - ((3) +())비n-1 1 u[n- 5) x[n] = () uln]+치() un-1] 4 n-1 n-1 3) 지[n] = (능() 6) x(n] = G)-G) u[n 1] u[n 1] 3
Transcribed Image Text:Im 1/2 Re -273 -1/4 n-1 17 yln] + n-: n-1 n- = (-G) +SG) 1) x[n] = 1/ + u[n] 5 (3 u[n 1] 4) x[n] 9 (4, n-1 n-1 2) 지미 - ((3) +())비n-1 1 u[n- 5) x[n] = () uln]+치() un-1] 4 n-1 n-1 3) 지[n] = (능() 6) x(n] = G)-G) u[n 1] u[n 1] 3
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