ILLUSTRATIVE EXAMPLES 1. A grade of 4,2% grode intersech a grode of +3.0% at Station 11 + 488.00 of elevations 20.80 meters. These two center gradelines are to be connected by a 260 meter vertical parabolic curve. a) Al what station is the cros drainage pipes be situated bị it the overal outside dimensions of the reintorced concrete pipe to be instoled is 95 cm. and the top of the culvert is 30 cm below the subgrade, what wil be the invert elevation at the centert From the grade diagram 200 0,042 0.042+ 0.03 S = 151.67 m 130 m 130 m 1.2% PI Sta 11+488 Elev 20.80 Lowest point 0.03 0.03 d- S,- 130 - 151.07 - 130 d= 21.67 m The eross-drainage pipe should be at the lowest point of the eurve. Stationing of the lowest point indicated as point A in the figure: Sta A = Sta PI +d Sta A= 11488 +21.67 = 11509.67 Sta A= 11+500.67 km
ILLUSTRATIVE EXAMPLES 1. A grade of 4,2% grode intersech a grode of +3.0% at Station 11 + 488.00 of elevations 20.80 meters. These two center gradelines are to be connected by a 260 meter vertical parabolic curve. a) Al what station is the cros drainage pipes be situated bị it the overal outside dimensions of the reintorced concrete pipe to be instoled is 95 cm. and the top of the culvert is 30 cm below the subgrade, what wil be the invert elevation at the centert From the grade diagram 200 0,042 0.042+ 0.03 S = 151.67 m 130 m 130 m 1.2% PI Sta 11+488 Elev 20.80 Lowest point 0.03 0.03 d- S,- 130 - 151.07 - 130 d= 21.67 m The eross-drainage pipe should be at the lowest point of the eurve. Stationing of the lowest point indicated as point A in the figure: Sta A = Sta PI +d Sta A= 11488 +21.67 = 11509.67 Sta A= 11+500.67 km
Chapter8: Influence Lines
Section: Chapter Questions
Problem 10P
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Question
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Resolve the #1 illustrative problem using the equations for a parabola. (y=Ax²+Bx+C)
Note: Your solution should not include the use of the grade diagram for the required. (#1a & #1b, & #2)
Transcribed Image Text:ILLUSTRATIVE EXAMPLES
1. A grade of -4.2% grode intersects a gode of +3.0% at Station 11 + 488.00 of
eievations 20.80 meters, These two center gradelines are le be connected by a 260
meter vertical paratiolic cutve.
a) At what station is the cros-drainage pipes be situated?
Dị it the overal outside dimensiors ol the reintorced concrete pipe to be instaled is
75 cm. and the top of the culvert is 30 cm below the subgrade, what wl be the
invert elevation at the center?
From the grade diagram:
200
0,042 +0.03
0,042
S = 151.67 m
130 m
130 m
S
PT
4.2%
PI Sta 11+488
E Iv 20.80
Lowest point
S
0.03
0.042
0.03
d- S - 130 - 151,07 - 130
d= 21.67 m
The cross-drainage pipe should be at the lowest point of the eurve. Stationing of the
lowest point indicated as point A in the figure:
Sta A = Sta PI + d
Sta A= 11488 +21.67 = 11509.67
Sta A = 11+500.67 km
Transcribed Image Text:Vertical distaner between PC and PI:
a= 130(0.042)
a=5,46 m
Vertical distance between PCand the lowest point A:
A, = 5,(0.042) - ja51.67)(0.042)
A, = 3.18 m
Elevation of the lowest point A:
Elev A- Elev PI+a- A,
Elev A 20.80 +5.46 - 3.18
Elev A= 23.08 m
PC
PT
0.30 m
0.95 m
Invert
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