Illustration Procedure/Observation/Discussion Procedure: Simply blow up two balloons to equal size, place one on ice and one in just boiled water. What happened to the volume of the balloons? Observation: (1)_ Discussion: The increase in temperature will force the air to increase its (2). thus expanding the balloon. It will look like the balloon is growing or inflating inside the container with hot water Figure 2 Balloons in hot and cold water

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Illustration
Procedure/Observation/Discussion
Procedure: Simply blow up two balloons to equal size, place one
on ice and one in just boiled water. What happened to the
volume of the balloons?
Observation: (1)_
Discussion: The increase in temperature will force the air to
increase its (2).
thus expanding the balloon. It will
look like the balloon is growing or inflating inside the container
with hot water
Figure 2 Balloons in hot and cold water
Transcribed Image Text:Illustration Procedure/Observation/Discussion Procedure: Simply blow up two balloons to equal size, place one on ice and one in just boiled water. What happened to the volume of the balloons? Observation: (1)_ Discussion: The increase in temperature will force the air to increase its (2). thus expanding the balloon. It will look like the balloon is growing or inflating inside the container with hot water Figure 2 Balloons in hot and cold water
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