10. A 5.0 mol sample of oxygen has a volume of 2.3 L, the pressure is 1.2 atm, and the temperature is 315 K. If the volume increases to 6.1 L, the moles increases to 7.0 moles, and the pressure increases to 3.4 atm, what will the new temperature of the oxygen gas be? a. 1690 K b. 0.254 K C. 338 K d. 591 K
10. A 5.0 mol sample of oxygen has a volume of 2.3 L, the pressure is 1.2 atm, and the temperature is 315 K. If the volume increases to 6.1 L, the moles increases to 7.0 moles, and the pressure increases to 3.4 atm, what will the new temperature of the oxygen gas be? a. 1690 K b. 0.254 K C. 338 K d. 591 K
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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9. What is the pressure of a 0.322-mol sample of chlorine that has a volume of 4.42 L at 400°C?
a. 4.03 atm
b. 17.8 atm
C. 0.78 atm
d. 0.248 atm
10. A 5.0 mol sample of oxygen has a volume of 2.3 L, the pressure is 1.2 atm, and the temperature is 315 K. If
the volume increases to 6.1 L, the moles increases to 7.0 moles, and the pressure increases to 3.4 atm, what will
the new temperature of the oxygen gas be?
I
a. 1690 K
b. 0.254 K
C. 338 K
d. 591 K
Expert Solution
Step 1
To Calculate the new temperature we must have to use the equation of ideal gas law
PV = n RT
we have given two cases
case- I pressure of oxygen gas (P1) = 1.2atm
volume of oxygen gas (V1) = 2.3L
no of mole of oxygen gas (n1)= 5 mole
temperature of oxygen gas (T1) = 315 K
Case - II pressure of oxygen gas(P2) = 3.4atm
volume of oxygen gas (V2) =6.1L
no of mole of oxygen gas (n2) = 7 mole
temperature of oxygen gas (T2) = 'X' K
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