IIlustration 23.7. It was found that when a manufacturingprocess is under control, the average number of defectives per sam-ple batch of 10 is 1.2. What limits would you set in a quality con-trol chart based on the proportion of defectives in sample batches of10?

Answered: Image /qna-images/answer/4ef082d6-28ff-40ba-8423-52f44efc303f.jpg

Answered: Illustration 23.7. It was found that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The grade of OMG 321 was normally distributed with a mean of 81 and a standard deviation of 3. (round z value to the second decimal and probability to the fourth decimal place)
a.In an aquaculture study the following variables were measured on each fish: sex. Initial weight (g), bodytemperature (C), weight gain (g). For each variable indicate the scale of measurement. (b) A weed killer is to be applied at a rate of two ounces per 1000gallons of water (2oz/1000gallons). What is the application rate in ml/1000litrtrs if there are 28.375 ml/oz and 4.5liters/gallon? (c) The term test scores of 15 students enrolled in a Business statistics class were recorded inascending order as follows 4, 7, 7, 9, 10, 11, 13, 15, 15, 15, 17, 17, 19, 19, 20. After calculatingthe mean, median and the mode an error is discovered: one of the 15’s is really a 17. Of the threemeasures of central tendency which will change? (d) A student discovers that his grade on a recent test was the 72 nd percentile. If 90 students wrotethe test, then approximately how many students received a higher grade than he did?
8. An entrepreneur wanted to assess the quality of eggs produced by his subcontractors. He measured the weight (Y in g) of each egg in a selected pen as well as its circumference (X, in cm) to obtain the size. Define the population of the study.
Because the total population in 2050 is much larger than the Comparison of Population in the United States in 1950 and 2050 (in millions of persons) 1950 population, comparing percentages in each age group is clearer than comparing counts. Make a table of the Age Group 1950 2050 percentage of the total population in each age group for both Under 10 years | 29.3 | 56.2 1950 and 2050. 10 to 19 years 21.8 || 56.7 Only one age group in 1950 represents a larger percentage of the population than it does in 2050. For that age group, 20 to 29 years | 24.0 | 56.2 30 to 39 years | 22.8 | 55.9 determine the difference of the percentages between 1950 and 2050. Report your answer to the tenth of a percent. 40 to 49 years 19.3 52.8 50 to 59 years 15.5 || 49.1 60 to 69 years| 11.0 | 45.0 70 to 79 years 5.5 34.5 difference in percentages: % 80 to 89 years 1.6 | 23.7 90 to 99 years 0.1 8.1 100 years and 0.6 over Total 151.1 310.6
2.) Explain why the relative frequency column of a frequency table might not sum to 1.0.
1. The histogram below summarizes budgets for about 5000 movies. You may assume that values are evenly distributed between the endpoints of each interval. per milion dollars 51 1 0.5 0 (2.18) (0.876) 13 (0.42) (0.228) 50 75 100 (0.067) 200 Movie budgets (Millions of dollars) (0.0035) (a) What percent of movies had a budget between 50 and 100 million dollars? _% (b) Which describes more of the movies (circle one)? budget from $75M-$100M OR budget from $100M-$200M (c) Which is larger (circle one)? median budget OR average budget (d) Calculate the median budget for this dataset. $. million
Step 3 (b) Construct the upper and lower limits for a p chart for the manufacturing process, assuming each sample has 100 calls. Ap chart is a control chart that is used for proportion-defective data. The upper control limit, UCL, and lower control limit, LCL, are calculated as follows where p is the sample proportion of defective items and o- is the standard error of the proportion based on the samples of size n. UCL = p + 30- LCL %3D р — Зо- where Р(1 — р) 0- = p If sample proportions are within the UCL and LCL, then the process is said to be in control. If the LCL is calculated to be a negative value, then it is set to 0. The sample proportion of calls not resulting in a satisfactory outcome was found to be p = 0.051. There were 10 samples of 100 calls each, so we have n = Substitute these values in the formula for the upper control limit, rounding the result to four decimal places. UCL = p + 30- p(1 – p) = p + 3 0.051(1 – 0.051) = 0.051 + 3 Submit Skip (you cannot come back)
10. In order to stndy the output of a machine that fils boxes with certal, a quality control engineer Swmighed 150 boxes of Brand X cereal. The frequen- cy distribetion in Figure 4..20 summarizes her find- ings. Construct a histogram to represent the data. I- Weight (in ounces) Number of Bares 15.3 SI<15.6 13 15.6 sx<15.9 24 15.9 SI<16.2 84 16.2 SI<16.5 19 16.5sx<16.8 10 FIGUSE 4 n
9. It is thought that prehistoric Indians did not take their best tools, pottery, and household items when they visited higher elevations for their summer camps. It is hypothesized that archaeological sites tend to lose their cultural identity and specific cultural affiliation as the elevation of the site increases. Let x be the elevation (in thousands of feet) of an archaeological site in the southwestern United States. Let y be the percentage of unidentified artifacts (no specific cultural affiliation) at a given elevation. The following data were obtained for a collection of archaeological sites in New Mexico. 5.35 18 5.67 6.25 6.75 7.25 y 12 33 37 62 n USE SALT Complete parts (a) through (e), given Ex = 31.27, Ey = 162, Ex² = 197.9589, Ey² = 6770, Exy = 1069.84, and r= 0.9390. (c) Find x, and y. Then find the equation of the least-squares line ŷ= a + bx. (Round your answer to four decimal places.) (d) (e) Find the value of the coefficient of determination r2. What percentage of the…
6. For the data set with u = 50 and o = 5 What percent of the data is between... 45 and 50 45 and 55 40 and 50 60 and 65 50 and 65 above 50
1. Report the answer with the correct number of significant figures: a b C d e |f 6.0 g Ih li lj 1.4 +2.35 = 7.635 +2.34 = 13.627 -1 = 11.681 3.2 = 14.40 +2.6 - 7.211 = 13.60*3= |27.1*3.47 = 69.3 / 2.467 = 47.321/5.7 = 72.367/8.34 * 2.1 =

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Illustration 23.7. It was found that when a manufacturing process is under control, the average number of defectives per sam- ple batch of 10 is 1.2. What limits would you set in a quality con- trol chart based on the proportion of defectives in sample batches of 10?