If sample proportions are within the UCL and LCL, then the process is said to be in control. If the LCL is calculated to be a negative value, then it is set to 0. The sample proportion of calls not resulting in a satisfactory outcome was found to be p = 0.051. There were 10 samples of 100 calls each, so we haven = Substitute these values in the formula for the upper control limit, rounding the result to four decimal places. UCL = p + 3o- Р (1 — р) = p + 3 in 0.051(1 – 0.051) = 0.051 + 3. %3D
If sample proportions are within the UCL and LCL, then the process is said to be in control. If the LCL is calculated to be a negative value, then it is set to 0. The sample proportion of calls not resulting in a satisfactory outcome was found to be p = 0.051. There were 10 samples of 100 calls each, so we haven = Substitute these values in the formula for the upper control limit, rounding the result to four decimal places. UCL = p + 3o- Р (1 — р) = p + 3 in 0.051(1 – 0.051) = 0.051 + 3. %3D
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Step 3
(b) Construct the upper and lower limits for a p chart for the manufacturing process, assuming each
sample has 100 calls.
Ap chart is a control chart that is used for proportion-defective data. The upper control limit, UCL, and lower
control limit, LCL, are calculated as follows where p is the sample proportion of defective items and o- is the
standard error of the proportion based on the samples of size n.
UCL = p + 30-
LCL %3D р — Зо- where
Р(1 — р)
0- =
p
If sample proportions are within the UCL and LCL, then the process is said to be in control. If the LCL is
calculated to be a negative value, then it is set to 0.
The sample proportion of calls not resulting in a satisfactory outcome was found to be p =
0.051. There were
10 samples of 100 calls each, so we have n =
Substitute these values in the formula for the upper control limit, rounding the result to four decimal places.
UCL =
p + 30-
p(1 – p)
= p + 3
0.051(1 – 0.051)
= 0.051 + 3
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