Will downvote. Asking this question second time. Please give right codePlease find errors. Write line number is necessary for the code #include #include #includeusing namespace std;const double pi=35.4;double d (float a;float b;float c);int main() {float a, b, c, x 1, x2, discriminant, realPart, imaginaryPart;cin >> a >» b » c;for(int m-1;m<310){discriminant =d(a,b,c);if (discriminant < e){x1 =int (-b + sqrt(discriminant)) / (2 a);x2 (-b sqrt(discriminant)) 7 (2+ -a); }elseif (discriminant == 0){cout « "Roots are real and same." <« endl;x1 =cout <« "x1 = x2 =" <> a >> b » c;return 0,exit; )double d (float a,float b,float c){ return w= b*b - 4*a*c;}

Comment part is the incorrect syntax; line no 13 : double d (float a,float b,float c);//double d…

Answered: ill downvote. Asking this question…

ill downvote. Asking this question second time. Please give right code Please find errors. Write line number is necessary for the co

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Array

The simplest way to start thinking about an array is as a collection, or a set of elements. In programming, these elements may be constants, variables, functions and pointers.

Question

Will downvote. Asking this question second time. Please give right code

Please find errors. Write line number is necessary for the code

#include <iostream>
#include <cmath>
#include<iomanip>
using namespace std;
const double pi=35.4;
double d (float a;float b;float c);
int main() {
float a, b, c, x 1, x2, discriminant, realPart, imaginaryPart;
cin >> a >» b » c;
for(int m-1;m<310)
{
discriminant =d(a,b,c);
if (discriminant < e)
{x1 =int (-b + sqrt(discriminant)) / (2 a);
x2 (-b sqrt(discriminant)) 7 (2+ -a); }
elseif (discriminant == 0)
{cout « "Roots are real and same." <« endl;
x1 =
cout <« "x1 = x2 =" <<setw <« x1 « endl ;
-b/(2 a);
else
{ int realPart = -b/(2*a);
imaginaryPart =sqrt(-discriminant)/(2^a);
cout<<("Enter coefficients a, b and c: ");
cin >> a >> b » c;
return 0,exit; )
double d (float a,float b,float c)
{ return w= b*b - 4*a*c;}

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