IL Q.12: The non-sinusoidal applied voltage for the circuit shown is: (e;=5+4sin1000t+2sin3000t) V. 1. Derive the equation of currents (i) & (ic). 2. Find the total power consumed in the circuit? (Ans.: iT=1+0.73sin(1000t-24°)A, ic=0.09sin(1000t+ 155.8°)A & P7=6.33W) eT :-J180 122
IL Q.12: The non-sinusoidal applied voltage for the circuit shown is: (e;=5+4sin1000t+2sin3000t) V. 1. Derive the equation of currents (i) & (ic). 2. Find the total power consumed in the circuit? (Ans.: iT=1+0.73sin(1000t-24°)A, ic=0.09sin(1000t+ 155.8°)A & P7=6.33W) eT :-J180 122
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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![1T
1L
Q.12: The non-sinusoidal applied voltage for the
circuit shown is: (e,=5+4sin1000t+2sin3000t) V.
1. Derive the equation of currents (i) & (ic).
2. Find the total power consumed in the circuit?
(Ans.: iT=1+0.73sin(1000t-24°) A, İc=0.09sin(1000t+155.8°)A & P;=6.33W)
eT
1C
-J180 J22](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a132865-e9c2-4090-b5e6-9c4081959450%2Ffbd83de8-be78-40e7-8a0b-1d898d740597%2Fzzcs3uo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1T
1L
Q.12: The non-sinusoidal applied voltage for the
circuit shown is: (e,=5+4sin1000t+2sin3000t) V.
1. Derive the equation of currents (i) & (ic).
2. Find the total power consumed in the circuit?
(Ans.: iT=1+0.73sin(1000t-24°) A, İc=0.09sin(1000t+155.8°)A & P;=6.33W)
eT
1C
-J180 J22
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