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iii. How much current will enter the branch BE? Here R3 and R5 are in parallel so, R3|| R5=3.3/2=1.65kohm 10-B/R1=B/R2=B/R2+B/Req+R4 10-B/1.5*10^3=B/1.5*10^3+B/2.12*10^3 6.66=1.805*B B=3.689V Current in BC=3.689/2.12*10^3=1.74 mA

iii. How much current will enter the branch BE? Here R3 and R5 are in parallel so, R3|| R5=3.3/2=1.65kohm 10-B/R1=B/R2=B/R2+B/Req+R4 10-B/1.5*10^3=B/1.5*10^3+B/2.12*10^3 6.66=1.805*B B=3.689V Current in BC=3.689/2.12*10^3=1.74 mA

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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R6 2K Ohm 3KOhm R3 1.5K Ohm 3.3KChm V1 R2 1.5K Ohm, 10V R4 47KOhn
Transcribed Image Text:R6 2K Ohm 3KOhm R3 1.5K Ohm 3.3KChm V1 R2 1.5K Ohm, 10V R4 47KOhn
iii. How much current will enter the branch BE? Here R3 and R5 are in parallel so, R3|| R5=3.3/2=1.65kohm 10-B/R1=B/R2=B/R2+B/Req+R4 10-B/1.5*10^3=B/1.5*10^3+B/2.12*10^3 6.66=1.805*B B=3.689V Current in BC=3.689/2.12*10^3=1.74 mA
Transcribed Image Text:iii. How much current will enter the branch BE? Here R3 and R5 are in parallel so, R3|| R5=3.3/2=1.65kohm 10-B/R1=B/R2=B/R2+B/Req+R4 10-B/1.5*10^3=B/1.5*10^3+B/2.12*10^3 6.66=1.805*B B=3.689V Current in BC=3.689/2.12*10^3=1.74 mA
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