III. Calculate the change in free energy if 0.335 moles of NaI is dissolved in water at 25.0°C 10. Consider the dissolution of NaBr and Nal. The values provided here will be helpful foranswering the following questions.| ΔΗAS+soln (kJ/mol)soln mol-KNaBr-0.06057.0Nal-7.5074.0I.Write a balanced equilibrium equation for the dissolution of Nal in water. Includephases.II.Which of the following explains why the entropy change is greater for thedissolution of Nal compared to the dissolution of NaBr?A. The cation forms stronger ion-dipole networks with water in NaBr than Nalbecause of the weaker bond to Br.B. The interactions between bromide ions with other bromide ions is strongerthan the interactions between iodide ions with other iodide ions.C. The more negative change in enthalpy observed with Nal implies greaterdissociation and hence greater entropy.D. lodide has weaker ion-dipole interactions with water than bromide.E. The bromide ion has more negative charge than the iodide ion. Therefore,because of the greater charge, it forms a stronger ion-dipole network withwater.III.Calculate the change in free energy if 0.335 moles of Nal is dissolved in water at25.0°C.What is the dissolution of 1.00 mol of NaBr at 298.15 K?IV.

To calculate change in free energy ( ∆G° )., We would use value of ∆H°sol and ∆S°sol of NaI .

Answered: III. Calculate the change in free…

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III. Calculate the change in free energy if 0.335 moles of NaI is dissolved in water at 25.0°C

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.108PAE: 12.108 A nuclear engineer is considering the effect of discharging waste heat from a power plant...

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III. Calculate the change in free energy if 0.335 moles of NaI is dissolved in water at 25.0°C

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