III. 100 grams of HCl reacts with 96 grams of methanol CH3OH, producing chloromethane, CH3CI and water according to thefollowing equationCH3OH + HCICH3CI + H20a. What is the limiting reagent?b. How many grams of CH3CI will be produced?c. If 76 grams of CH3CI is actually produced, what is the percent yield?

Given: mass of HCl=100gm mass of CH3OH =96gm Molecular weight of HCl=1+35.5gmol=36.5gmol Molecular…

Answered: III. 100 grams of HCI reacts with 96…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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III. 100 grams of HCl reacts with 96 grams of methanol CH3OH, producing chloromethane, CH3CI and water according to the
following equation
CH3OH + HCI
CH3CI + H20
a. What is the limiting reagent?
b. How many grams of CH3CI will be produced?
c. If 76 grams of CH3CI is actually produced, what is the percent yield?

Expert Solution

Step 1

Given:

mass of HCl=100gm

mass of CH₃OH =96gm

$\begin{array}{rcl} M o l e c u l a r w e i g h t o f H C l & = & (1 + 35.5) \frac{g}{m o l} \\ = & 36.5 \frac{g}{m o l} \end{array}$

$\begin{array}{rcl} M o l e c u l a r w e i g h t o f C H_{3} O H & = & (12 + 4 \times 1 + 16) \frac{g}{m o l} \\ = & 32 \frac{g}{m o l} \end{array}$

$\begin{array}{rcl} M o l e c u l a r w e i g h t o f C H_{3} C l & = & (12 + 3 \times 1 + 35.5) \frac{g}{m o l} \\ = & 50.5 \frac{g}{m o l} \end{array}$

Step 2

(a) According to the reaction:

1 mole of HCl reacts with 1 mol of CH₃OH

36.5g of HCl reacts with 32g of CH₃OH

$100 g o f H C l r e a c t s w i t h = \frac{32}{36.5} \times 100 g o f C H_{3} O H = 87.6 g o f C H_{3} O H$

as mass of CH₃OH available is more than required. Hence, HCl is the limiting reagent

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