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- Please prove it46. Let X have a Standard Normal Distribution. Find a such that P(X > a) = 0.80511 %3| A. – 0.66 В. — 0.76 С. — 0.86 D. – 0.96The graph to the right portrays the decision criterion for a hypothesis test for a population mean u. The null hypothesis for the test is Ho:=Ho- The curve in the graph is the normal curve for the test statistic under the assumption that the null hypothesis is true. Complete parts (a) through (f) below. Reject | Do not reject Ho Ho I 0.04 -1.751 0 a. Determine the rejection region. OA. z> -1.751 O B. z>1.751 O C. zs - 1.751 OD. zs-1.751 or z2 1.751 b. Determine the nonrejection region. A. - 1.751 szS1.751 Question Viewer O B. B. - 1.751 -1.751 c. Determine the critical value(s). (Type integers or decimals. Do not round. Use a comma to separate answers as needed.) Click to select your answer(s). MacBook Pro F1 F2 F3 DII DD F4 F5 F6 F7 F8 F9 F10 23 & 4. 00 %24 2.
- 7. Assume that X and Y have a bivariate normal distribution having means 14.l and 1.3, and standard deviations 2.5 and 0.1, respectively, with correlation coefficient 0.8. Find P(Y >1.4|X =15) and P(X >15|Y = 1.4).15. The dean of a university estimates that the mean number of classroom hours per week for full-time faculty is 10.0. As a member of the student council, you want to test this claim. A random sample of the number of classroom hours for eightfull-time faculty for one week is shown in the table below. At α=0.05, can you reject the dean's claim? Complete parts (a) through (d) below. Assume the population is normally distributed. 11.2 7.5 12.2 7.2 4.1 9.5 13.7 8.5 Question content area bottom Part 1 (a) Write the claim mathematically and identify H0 and Ha. Which of the following correctly states H0 and Ha? A. H0: μ>10.0 Ha: μ≤10.0 B. H0: μ≠10.0 Ha: μ=10.0 C. H0: μ<10.0 Ha: μ≥10.0 D. H0: μ≤10.0 Ha: μ>10.0 E. H0: μ≥10.0 Ha: μ<10.0Q4) Suppose the diameter at breast height (in.) of trees of a certain type is normally distributed with u = 8.8 and o = 2.8, as suggested in the article "Simulating a Harvester-Forwarder Softwood Thinning". What value c is such that the interval includes 98% of all diameter values?
- time, i.e. P(μx-ox ≤ x ≤ μx + 0x). 3. Suppose that people heights are normally distributed with mean of 170 cm and standard deviation of 6 cm. a) What proportion of people are between 165 cm and 175 cm tall? b) Find the minimum ceiling of an airplane such that at most 5% of people walking down the aisle will have to duck. E c) Find the probability that the average height of a random sample of 49 people is greater than 172 cm. 80 F3 4 R % 5 T F6 Y 1 & 7 K ard deviation of the expected U 8 DIIThe pressure of air (in MPa) entering a compressor is measured to be X = 8.5 ± 0.2, and the pressure of the air leaving the compressor is measured to be Y = 21.2 ± 0.3. The intermediate pressure is therefore measured to be P = √XY = 13.42 . Assume that X and Y come from normal populations and are unbiased. a) From what distributions is it appropriate to simulate values X* and Y*? b) Generate simulated samples of values X*, Y*, and P*. c) Use the simulated sample to estimate the standard deviation of P. d) Construct a normal probability plot for the values P*. Is it reasonable to assume that P is approximately normally distributed? e) If appropriate, use the normal curve to find a 95% confidence interval for the intermediate pressure.33. If X is a normal variate with mean u and variance X- o? and P - b< .22.Given a random sample of size n = 29, from a normal distribution, find k such that: a) P(-k < T < 1.313) = 0.88 b) P(-k < T < k) = 0.99 c) P(-2.286 < T < k) = 0.685state whether or not this resulting observed interval ended up capturing the true population proportion p of 0.45.3) Suppose test scores are measured by the Gaussian Normal Distribution N(X,75,10) calculate the following. a) Pr(80 < X < 90) b) Pr(50 < X < 70) c) The 95 th percentileSEE MORE QUESTIONS
