(iii)Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, tocalculate the electron affinity of chlorine:Cate)Ca(g)AHat = +190 kJ/mol2+Ca ()AHIE = +1730 kJ/molCa@)2e-AHat = +121 kJ/molCa (o)CaCl26)AHLE = -2184 kJ/mol2+%3!Ca(s) +Cla)CaClae)AHF = -795 kJ/mol (i) Match the following enthalpy changes with the reactions below: enthalpy change ofcombustion, enthalpy change of formation, enthalpy change of solution, enthalpy change ofhydration, enthalpy change of atomisation, enthalpy change for ionisation, enthalpy change forelectron affinity:13H2 (9) +O2 (o)CH:CH2OH () AH =20 (s) +2NHa (a)So? (a)AH =+(NH.)2SO4 (9)AH =Na'(g)Na (ag)O2 (a)CO2 (9)AH =C (e)AH =Na (g)Na (s)ΔΗ-Na'(g)eNa (g)cI (g)Nacl (s)AH =Na' (g)(ii) Identify the different enthalpy changes and construct the Born-Haber cycle for the formation ofsodium choride (NaCI) using the information below. Calculate the missing enthalpy change valueNacl (s)AH° = ?Na'@)AH° = +121 kJmol"Cl2 (4)Cl (g)AH° = -364 kJmol"(g)AH° = +108 kJmol"Na (s)Na (a)AH° = +500 kJmol"Na (a)Na' o +eCl2 (g)NaCl (9)AH° = -411 kJmol"Na (e)+

Born Haber cycle is used to calculate heat of formation or lattice energy of an ionic compound. It…

(iii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca() Ca@) AHat = +190 kJ/mol Ca) Ca (o 2e- AHIE = +1730 kJ/mol Claa) Cla) AHat = +121 kJ/mol Ca"() + CaClz) AHLE = -2184 kJ/mol Ca) + Cl2@) CaClae) AH: = -795 kJ/mol

(iii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca() Ca@) AHat = +190 kJ/mol Ca) Ca (o 2e- AHIE = +1730 kJ/mol Claa) Cla) AHat = +121 kJ/mol Ca"() + CaClz) AHLE = -2184 kJ/mol Ca) + Cl2@) CaClae) AH: = -795 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Quantum Chemistry

Quantum chemistry deals with the properties of chemical systems and their reactions. The branch of chemistry which is more concerned with quantum chemistry is physical chemistry. It is a more sophisticated field of theoretical physics which is concerned towards the application of physical concepts towards various chemical aspects such as, formation of atoms, chemical structure descriptions, chemical bond strength, hybridization, conjugation etc. Quantum chemistry mainly studies the various states i.e., ground state, excited state, transition states of the individual atoms or molecules taking place during any chemical reaction. The laws of motion explained by various scientists, which are termed as “classical mechanics” were not acceptable in terms of electrons, protons, atoms, light etc. Thus, a new theory named “quantum mechanics” emerged to understand the basic framework of various atomic and subatomic particles.

Question

100%

(iii)
Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to
calculate the electron affinity of chlorine:
Cate)
Ca(g)
AHat = +190 kJ/mol
2+
Ca ()
AHIE = +1730 kJ/mol
Ca@)
2e-
AHat = +121 kJ/mol
Ca (o)
CaCl26)
AHLE = -2184 kJ/mol
2+
%3!
Ca(s) +
Cla)
CaClae)
AHF = -795 kJ/mol

(i) Match the following enthalpy changes with the reactions below: enthalpy change of
combustion, enthalpy change of formation, enthalpy change of solution, enthalpy change of
hydration, enthalpy change of atomisation, enthalpy change for ionisation, enthalpy change for
electron affinity:
1
3H2 (9) +
O2 (o)
CH:CH2OH () AH =
20 (s) +
2NHa (a)
So? (a)
AH =
+
(NH.)2SO4 (9)
AH =
Na'(g)
Na (ag)
O2 (a)
CO2 (9)
AH =
C (e)
AH =
Na (g)
Na (s)
ΔΗ-
Na'(g)
e
Na (g)
cI (g)
Nacl (s)AH =
Na' (g)
(ii) Identify the different enthalpy changes and construct the Born-Haber cycle for the formation of
sodium choride (NaCI) using the information below. Calculate the missing enthalpy change value
Nacl (s)
AH° = ?
Na'@)
AH° = +121 kJmol"
Cl2 (4)
Cl (g)
AH° = -364 kJmol"
(g)
AH° = +108 kJmol"
Na (s)
Na (a)
AH° = +500 kJmol"
Na (a)
Na' o +
e
Cl2 (g)
NaCl (9)
AH° = -411 kJmol"
Na (e)
+

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