II. Using the digits 1, 2, 3 and 5, solve the number of 3-digit numbers that can be formed if: 4. The number is divisible by 5, Solution: 3 x 2 x1 6 numbers IH. The code for a safe is of the form XX XX YYY where X is any number from 0 to 9 and Y represents the letters of the alphabet. Solve the number of possible cases when: 6. the digits and letters of the alphabet can be repeated, but the code may not contain a zero or any of the vowels in the alphabet. Solution: 9 x9 x 9 x9x 21 x 21 x 21 = 9* x 213 7. the digits and letters of the alphabet can be repeated, but the digits may only be prime numbers. Solution: 4 x 3 x 2 x 1 x26 × 25 × 24 = 374,400

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Question
II. Using the digits 1, 2, 3 and 5, solve the number of 3-digit numbers that can be
formed if:
4. The number is divisible by 5,
Solution: 3 x 2 x1= 6 numbers
IH. The code for a safe is of the form XXXXYYY where X is any number from 0
to 9 and Y represents the letters of the alphabet. Solve the number of possible
cases when:
6. the digits and letters of the alphabet can be repeated, but the code
may not contain a zero or any of the vowels in the alphabet.
Solution: 9 x9x 9 x 9 x 21 x 21 x 21 = 9* x 213
7. the digits and letters of the alphabet can be repeated, but the digits
may only be prime numbers.
Solution: 4 X 3 x 2 X 1 x 26 × 25 × 24 = 374,400
Transcribed Image Text:II. Using the digits 1, 2, 3 and 5, solve the number of 3-digit numbers that can be formed if: 4. The number is divisible by 5, Solution: 3 x 2 x1= 6 numbers IH. The code for a safe is of the form XXXXYYY where X is any number from 0 to 9 and Y represents the letters of the alphabet. Solve the number of possible cases when: 6. the digits and letters of the alphabet can be repeated, but the code may not contain a zero or any of the vowels in the alphabet. Solution: 9 x9x 9 x 9 x 21 x 21 x 21 = 9* x 213 7. the digits and letters of the alphabet can be repeated, but the digits may only be prime numbers. Solution: 4 X 3 x 2 X 1 x 26 × 25 × 24 = 374,400
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