II. Solve the following problems. 1. Mendel crossed a plant that was heterozygous for height and heterozygous for pea shape with a plant that was homozygous dominant for height and heterozygous for pea shape. What are the possible genotypes and phenotypes of the offspring? • Dominant for height = T (tall) • Recessive for height = t (short) • Dominant for pea shape = R (round) • Recessive for pea shape = r (wrinkled) P1:

II. Solve the following problems. 1. Mendel crossed a plant that was heterozygous for height and heterozygous for pea shape with a plant that was homozygous dominant for height and heterozygous for pea shape. What are the possible genotypes and phenotypes of the offspring? • Dominant for height = T (tall) • Recessive for height = t (short) • Dominant for pea shape = R (round) • Recessive for pea shape = r (wrinkled) P1:

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 7GP: Several alleles affect traits of roses, such as plant form and bud shape. Alleles of one gene govern...

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1. Use the following information to answer the question: Parental cross is RrYy x RrYy Seed Shapes are R-round, r-wrinkled Seed colors are Y-yellow, y-green Based on the information given, what is the phenotype ratio of the offspring of this cross? 2. A pea plant heterozygous for height and seed color (TtYy) is crossed with a pea plant heterozygous for height but homozygous recessive for seed color (Ttyy). If 80 offspring are produced, how many are expected to be tall and have yellow seeds? 3. What is the chromosome theory of inheritance? How does this theory explain Mendel's results? 4. A cross between two organisms heterozygous for two different genes (AaBb) results in a 9:3:3:1 phenotype ratio among the offspring. Is the offspring's genotype ratio the same? Explain your answer.…
Direction: Answer the following problems: 1. Predict the phenotypic ratios of offspring when a homozygous white cow is crossed with a roan bull. Illustrate using a Punnett square. 2. Complete the Punnett square for a cross between a black chicken (BB) and a white chicken (WW). Give the phenotype of the offspring in the F1 generation. Кey BB – black ww- white F1 BW – checkered Phenotype:
1. Complete the Punnett square for a cross between a homozygous red-flowered snapdragon (RR) and a homozygous white-flowered snapdragon (WW). Give the ratio for the phenotype and the genotype. Key F1 Genotypic Ratio: RR – red Phenotypic Ratio: wW- white RW- pink 2. Complete the Punnett Square for a cross between two Fi plants (WW). Give the phenotypic ratio for the F2 generation. F2 Phenotypic ratio: 3. Cite some possible applications of genetics to plant breeding.
a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…
1. Solve monohybrid and dihybrid cross genetic outcomes utilizing branch diagrams and/or Punnett squares. 2. Apply and demonstrate the law of segregation and law of independent assortment
Consider a cross to investigate the pea pod texture trait, involving constricted or inflated pods. Mendel found that the traits behave according to a dominant/ recessive pattern in which inflated pods were dominant. If you performed this cross and obtained 650 inflated-pod plants in the F2 generation, approximately how many constricted-pod plants would you expect to have? 600 165 217 468
The dominant C allele of a gene that controls color in corn produces kernels with color; plants homozygous for a recessive c allele of this gene have colorless or white kernels. What kinds of gametes, and in what proportions, would be produced by the plants in the following crosses? What seed color, and in what proportions, would be expected in the offspring of the crosses? a. CCCc b. Cccc c. CcCc
Two pairs of traits are segregating in a cross. Two parents produce 156 progeny that fall into 4 phenotypes. The numbers of offspring in the 4 phenotypes are 89, 31, 28, and 8. What are the genotypes of the two parents?
7. In pea plants, inflated pod is governed by a completely dominant gene and a constricted pod by a recessive gene. Another independently segregating dominant gene produces green pod while recessive gene produces yellow pod. Give the genotypes of the parents in each of the crosses given below. Phenotypes of Offspring Inflated yellow Constricted yellow Parental Phenotypes Parental genotypes Inflated groen Constricted Green 7.1. inflated green x inflated yellow 58 62 18 22 7.2. constricted green x constricted green 56 18 7.3 inflated yellow x inflated yellow 64 20 74. inflated gr green x 36 38 inflated yellow 7.5. inflated green x inflated green 178 62 58 22
I. In an exotic Peruvian plant, burgundy flowers (B) are dominant to pink flowers (b), green stalks (G) are dominant to yellow (g) and hairy leaves (H) are dominant to smooth leaves (h). What is the probability that the following pair of parents will produce the indicated offspring? Parent 1 = BbGgHh x Parent 2 = BBGghh -> Offspring = BBgghh Punnett squares for each individual trait can help you with this: 000 Parent 1 Parent 2 Probability= (BB) What is the phenotype of BBgghh? Which of the following options are gametes that Parent 1 can produce? Circle the correct one(s). hh BGH Bgh Bb bGh BgH Gg bGH BbGghh (gg) X (hh)
1. Mendel obtained his initial pea plant varieties from local breeders who were developing new varieties that might be useful or interesting. To generate these new varieties, breeders formed hybrids between existing varieties of different phenotypic characteristics by cross pollination, using techniques they doubtless taught to Mendel. After producing a hybrid, they allowed several generations of self-pollination, as happens naturally if the flowers are not disturbed. a. How many generations would it take for a breeder to have produced new pure-breeding varieties using this approach? iv. What is the probability that an individual in each of these generations (F2, F3, and F10) would be homozygous for one or the other allele of this gene? [Broad hint: if they’re not heterozygous, they’re homozygous!]
7. In pea plants, inflated pod is governed by a completely dominant gene and a constricted pod by a recessive gene. Another independently segregating dominant gene produces green pod while recessive gene produces yellow pod. Give the genotypes of the parents in each of the crosses given below. Phenotypes of Offspring Parental Phenotypes Parental genotypes Inflated Inflated Constricted Constricted yellow green yellow Green inflated green x inflated yellow 7.1. 58 62 18 22 7.2. constricted green x 56 18 constricted green 7.3 inflated yellow x 64 20 inflated yellow inflated green x inflated yellow 7.4. 36 38 inflated green x inflated green 7.5. 178 62 58 22