HELP II. PROBLEM 21)Find the Zee-transform of the sequence x[k]= u[-k].2)Determine the sequence x[k] whose Zee-transform is given byX(z)log(1+ az-), |z| > Ja|

1. We know that the z transform of a function is defined as Z{x[k]} = ∑0∞x[k]* z-n We know…

Answered: II. PROBLEM 2 1) Find the Zee-transform…

II. PROBLEM 2 1) Find the Zee-transform of the sequence ¤[k] = ul-k). 2) Determine the sequence r[k] whose Zee-transform is given by X(z) log(1+az-1), |z| > |a|

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.16P

See similar textbooks

Related questions

Q: Vc. Vec=SV Vee-25V Bzl00 Ve RE=2KR 3 RE Find leiIc Ia, VeE and made of Operaten.

Q: All of the following statements about the TRIAC could be true except: OA. TRIACS are not used in…

A: TRIAC:- A TRIAC is a three-terminal AC switch that differs from conventional silicon-controlled…

Q: 5. Using k, = 0.1 V.s/rad, evaluate the steady-state error e(t) for the ramp slope Ro, as de- fined…

A: given that ramp slope frequency f = 0.4 Hz

Q: 1.00 1 1 W R₁ ww 2bo Find the g parameters for the circuit in (Figure 1). Take R₁ = 2, R₂ = 15, R₂ =…

Q: A2a R A26 Figure Q3a Figure Q3a shows the circuit schematic of part of an instrumentation amplifier.…

Q: Please answer in typing format solution

A: Detailed explanation:Factors Contributing to Power Quality Issues and Their MitigationPower quality…

Q: 85[1+0.4432/1-.85(sqrt(48.2625/V))]=100 Solve for V

Q: Need help finding TF

A: Given: Block diagram of a control system. Formula and concept: Transfer function: Transfer function…

Q: What is the boolean expression for the logic gate in the picture?

A: The given circuit is

Q: step by step solution and explain the process please no AI answer. handwritten very much appreciated

A: Problem 10.4 (a)Given:Signal h[n]: h[0] = 1, h[1] = -1, and h[n] = 0 for all other values of n.X[k]…

Question

HELP

II. PROBLEM 2
1)
Find the Zee-transform of the sequence x[k]
= u[-k].
2)
Determine the sequence x[k] whose Zee-transform is given by
X(z)
log(1+ az-), |z| > Ja|

Expert Solution

Step 1

1. We know that the z transform of a function is defined as

Z{x[k]} = $\sum_{0}^{\infty} x [k] * z^{- n}$

We know that Z{u[k]} =

$\frac{z}{z - 1} u \sin g t i m e s h i f t i n g p r o p e r t y i f Z {x [n]} = F (z) t h e n Z {x [- n]} = F (z^{- 1})$

this implies that Z{u[-k]} = $\frac{z^{- 1}}{z^{- 1} - 1}$

Step by step

Solved in 2 steps

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Question 2 (a) Determine the z-transform, including the ROC in z-plane and a sketch of the pole-zero-plot, for sequence: *[„]= a"u[n] (b) ) For the z-transform H(z) = 1/ (1 – 4z)( 1 /4 – v3/2z + z²) 2 Determine possible regions of convergence. In each case comment stability and causality of the system whose transfer function is H(z). What is the output of the stable system to the input x(n) = 2cos(nt/2)? (c) A causal discrete-time signal x(n) has the Fourier transform X(e"). Write its z-transform in terms of the Fourier transform of the discrete-time signal, i.e., write the z-transform value based on its values on the unit circle.
a) Find the z-transform of x(n) = d(n) + (0.2)"u(n) b) Given X(z) = |z|> 0.4 find its inverse z-transform x(n) by using partial fraction expansion. 5 +0.2z-¹ 1+0.2z-1-0.08z-2 c) z-transform Find X(z) for each x(n) signal below a. (0.5)¹u(n), b. (-0.5)¹u(n), d) inverse z-transform Given C. d. (2)"u(n), (-2)^u(n), 1+2z¹+z² X(z) = |z| > 1 11.5z-1 +0.5z-² find its inverse z-transform x(n) by using partial fraction expansion.
3. Find the inverse z-transform of each of the following z-transforms. Determine the poles and zeros of each z-transform. a) X(z) = b) X(z) = c) X(z) = d) X(z) = 1-z-1 1-42-2 1-z-1 1-42-2 |z|>2 |z| 3 1 (1-32-1)2 12>2
1. If a system function has zeros at the origin of the z-plane then the system function is a properrational function. Why? 2. Can you obtain the z-transform of u[n] at z = 0? If you can, what is its value? If you cannot,why not? 3. What is the preferred method for obtaining the inverse z-transform of rational functions?Describe this method. 4. Explain why a one-sided z-transform is able to determine response to a LCCDE with initialconditions while the two-sided z-transform cannot. 5. Can any system with a rational system function be decomposed into a product of an allpasssystem and a minimum-phase system? If yes, then explain how?
According to Time shifting property of z-transform, if X(z) is the z-transform of x(n) then what is the z-transform of x(n-k)?a) zkX(z)b) z-kX(z)c) X(z-k)d) X(z+k)
If Z{x1(n)}=X1(z) and Z{x2(n)}=X2(z) then what is the z-transform of correlation between the two signals?a) X1(z).X2(z-1)b) X1(z).X2(z-1)c) X1(z).X2(z)d) X1(z).X2(-z)
12 By first resolving Y(z)/z into partial fractions, find Inverse Z- transform (g) 22²-7z (z-1)²(z-3)
show all you work
For each of the following z-domain functions, determine the (causal) sampled time function using the z-transform tables of one-sided z-transform transform pairs and attributes. Assume the one-sided z-transform requires a Region of Convergence of |z| > 1.
QUESTION 4 Z-transform of any điscrete -time signal can be defined using expression below, +00 X(Z) = ) x[n]z-n, x,[n] = a"u[n] x2[n] = -a"u[-n – 1] (b) Instead of having the same X(Z) expression, prove that, both discrete-time signals having different ROC.
Q6
H.W. Prove the z-transforms for common sequences summarized in Table 1 except the last sequence (15). Table 1 Table of z-Transform Pairs Region of Convergence Line No. x(n), n20 z-Transform X(z) x(n) 2 8(n) 1 kl>0 az au(n) kl>1 Z-1 nu(n) kl>1 (z – 1)? z(z+1) nu(n) kl>1 (z – 1)3 a u(n) Iz|> la| Z-a e-na u(n) kl>ea (z -ea) 8. az na" u(n) kl> la| (2- a) z sin(a) z2 – 2z cos(a) +1 sin(an)u(n) kl>1 z[z – cos(a)] z2 – 2z cos(a) +1 10 cos(an)u(n) kl>1 [a sin(b)]z z2 - [2a cos(b)]z +a? zz - a cos(b)] z2 - [2a cos(b)]z +a 11 a" sin(bn)u(n) z| > la| 12 a" cos(bn)u(n) kl> la| (e sin(b)]z 2a z? - [2e "cos(b)z +e 13 e an sin(bn)u(n) kl>ea zz -e cos(b)] z2 - [2e-a cos(b)]z +e-2a 14 an cos(bn)u(n) kl>e • e Az A*Z 2|A||P|"cos(n0 + o)u(n) where P and A are complex constants defined by P = |P|Z0, A = |AZ 15 Z-P Z- P* 6,