(II) Oxygen diffuses from the surface of insects to the interior through tiny tubes called tracheae. An average trachea is about 2 mm long and has cross-sectional area of 2 × 10-9 m². Assuming the concentration of oxygen inside is half what it is outside in the atmosphere, (a) show that the concentration of oxygen in the air (assume 21% is oxygen) at 20°C is about 8.7 mol/m³, then (b) calculate the diffusion rate J, and (c) estimate the average time for a molecule to diffuse in. Assume the diffusion constant is 1 x 10-5 m²/s.
(II) Oxygen diffuses from the surface of insects to the interior through tiny tubes called tracheae. An average trachea is about 2 mm long and has cross-sectional area of 2 × 10-9 m². Assuming the concentration of oxygen inside is half what it is outside in the atmosphere, (a) show that the concentration of oxygen in the air (assume 21% is oxygen) at 20°C is about 8.7 mol/m³, then (b) calculate the diffusion rate J, and (c) estimate the average time for a molecule to diffuse in. Assume the diffusion constant is 1 x 10-5 m²/s.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:(II) Oxygen diffuses from the surface of insects to the
interior through tiny tubes called tracheae. An average
trachea is about 2 mm long and has cross-sectional area of
2 × 10-9 m². Assuming the concentration of oxygen inside
is half what it is outside in the atmosphere, (a) show that
the concentration of oxygen in the air (assume 21% is
oxygen) at 20°C is about 8.7 mol/m³, then (b) calculate the
diffusion rate J, and (c) estimate the average time for a
molecule to diffuse in. Assume the diffusion constant is
1 x 10-5 m²/s.
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