II 15 b. (0.00763 x 10-28) (5.070 x 10-23) (0.0033 x 1013) C. (8.10 x 10-32)-1/2 = d. (0.08 liter atm mol-1 K-1) (760 torr atm-1) (440 K) = (1.6 x 10-2 liter)
II 15 b. (0.00763 x 10-28) (5.070 x 10-23) (0.0033 x 1013) C. (8.10 x 10-32)-1/2 = d. (0.08 liter atm mol-1 K-1) (760 torr atm-1) (440 K) = (1.6 x 10-2 liter)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter11: Properties Of Solutions
Section: Chapter Questions
Problem 4ALQ
Related questions
Question
![II
15
b.
(0.00763 x 10-28)
(5.070 x 10-23) (0.0033 x 1013)
C. (8.10 x 10-32)-1/2 =
d. (0.08 liter atm mol-1 K-1) (760 torr atm-1) (440 K) =
(1.6 x 10-2 liter)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3a43a41-1eba-4a0c-9c43-03e4c394a4ca%2F3b53cfe6-23bc-4427-8f10-7629f66b00de%2Fljl6jx.jpeg&w=3840&q=75)
Transcribed Image Text:II
15
b.
(0.00763 x 10-28)
(5.070 x 10-23) (0.0033 x 1013)
C. (8.10 x 10-32)-1/2 =
d. (0.08 liter atm mol-1 K-1) (760 torr atm-1) (440 K) =
(1.6 x 10-2 liter)
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