If {u,v,w} is linearly independent in a vector space V, which of the following is the correct proof to show that {u,v} is linearly independent? A. αu+βv=0 implies αu+βv+0w=0 implies α=β=0 B. αu+βv+γw=0 implies α=β=γ=0 implies αu+βv=0 C. αu+βv=0 implies αu+βv+γw=0 implies α=β=γ=0 D. α=β=0 implies αu+βv=0 E. αu+βv+γw=0 implies that α=β=γ=0 implies αu+βv=0

If {u,v,w} is linearly independent in a vector space V, which of the following is the correct proof to show that {u,v} is linearly independent? A. αu+βv=0 implies αu+βv+0w=0 implies α=β=0 B. αu+βv+γw=0 implies α=β=γ=0 implies αu+βv=0 C. αu+βv=0 implies αu+βv+γw=0 implies α=β=γ=0 D. α=β=0 implies αu+βv=0 E. αu+βv+γw=0 implies that α=β=γ=0 implies αu+βv=0

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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