will give like!this in c++ If you want a program to accept command-line arguments, how would you define the entry point tothe program?O int main(char "argv, int argc)O int main(int argc, const char "argv)int main(char argc, const char "argv)int main(int argc, const char "argv)int main(vector arguments)O int main(char argc, const char *"argv)

Answer: Correct Option (c) int main(int argc,const char** argv)

If you want a program to accept command-line arguments, how would you define the entry point to the program? int main(char "argv, int argc) int main(int argc, const char "argv) O int main(char argc, const char "argv) O int main(int argc, const char "argv) O int main(vector arguments)

If you want a program to accept command-line arguments, how would you define the entry point to the program? int main(char "argv, int argc) int main(int argc, const char "argv) O int main(char argc, const char "argv) O int main(int argc, const char "argv) O int main(vector arguments)

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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will give like!

this in c++

If you want a program to accept command-line arguments, how would you define the entry point to
the program?
O int main(char "argv, int argc)
O int main(int argc, const char "argv)
int main(char argc, const char "argv)
int main(int argc, const char "argv)
int main(vector<string> arguments)
O int main(char argc, const char *"argv)

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