If you threw the speaker with a speed of 13 m/s on a 28.5 °C day, what frequency does your stationary friend hear?  fobsfobs =    Hz      Part (b)  As you stand there, your friend puts the speaker in their dune buggy and drives away at a speed of 21 m/s as the song keeps playing. What frequency do you hear?  fobsfobs =    Hz  Part (c)  Instead of a fun day at the shore, let's reenact this scenario

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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On a fun day at the shore, you pitch your friend a wireless speaker that is playing a song that has a thick bass sound of 89 Hz.

Part (a)  If you threw the speaker with a speed of 13 m/s on a 28.5 °C day, what frequency does your stationary friend hear? 
fobsfobs =    Hz
 
   Part (b)  As you stand there, your friend puts the speaker in their dune buggy and drives away at a speed of 21 m/s as the song keeps playing. What frequency do you hear? 
fobsfobs =    Hz
 Part (c)  Instead of a fun day at the shore, let's reenact this scenario in the dead of winter, with a temperature of (-4.4 °C). What would be the answer to part (b) with this new, colder temperature? 
fobsfobs =    Hz
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