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If you had excess aluminum, how many moles of aluminum chloride could be produced from 26.0 g of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units.

If you had excess aluminum, how many moles of aluminum chloride could be produced from 26.0 g of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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If you had excess aluminum, how many moles of aluminum chloride could be produced from 26.0 g of chlorine gas, Cl2?
Express your answer to three significant figures and include the appropriate units.
 
I Review I Constants I Periodic Table In the following chemical reaction, 2 mol of A will react with 1 mol of B to produce 1 mol of A2B without anything left over: If you had excess chlorine, how many moles of of aluminum chloride could be produced from 21.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. 2A + B→A,B • View Available Hint(s) But what if you're given 2.8 mol of A and 3.2 mol of B? The amount of product formed is limited by the reactant that runs out first, called the limiting reactant. To identify the limiting reactant, calculate the amount of product formed from each amount of reactant separately: 0.778 mol Submit Previous Answers 1 mol A2B 2.8 metA x 1.4 mol A2B 2 metA Correct 1 mol A,B 3.2 metB x 3.2 mol A2B 1 metB Part B Notice that less product is formed with the given amount of reactant A. Thus, A is the limiting reactant, and a maximum of 1.4 mol of A2B can be formed from the given amounts. If you had excess aluminum, how many moles of aluminum chloride could be produced from 26.0 g of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units. • View Available Hint(s) HA ? Value Units Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining
Transcribed Image Text:I Review I Constants I Periodic Table In the following chemical reaction, 2 mol of A will react with 1 mol of B to produce 1 mol of A2B without anything left over: If you had excess chlorine, how many moles of of aluminum chloride could be produced from 21.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. 2A + B→A,B • View Available Hint(s) But what if you're given 2.8 mol of A and 3.2 mol of B? The amount of product formed is limited by the reactant that runs out first, called the limiting reactant. To identify the limiting reactant, calculate the amount of product formed from each amount of reactant separately: 0.778 mol Submit Previous Answers 1 mol A2B 2.8 metA x 1.4 mol A2B 2 metA Correct 1 mol A,B 3.2 metB x 3.2 mol A2B 1 metB Part B Notice that less product is formed with the given amount of reactant A. Thus, A is the limiting reactant, and a maximum of 1.4 mol of A2B can be formed from the given amounts. If you had excess aluminum, how many moles of aluminum chloride could be produced from 26.0 g of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units. • View Available Hint(s) HA ? Value Units Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining
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