If X iş an integer variable that I have yalue of o K9 is an integer variable of value 1, then when executing the next piece of code, the output of the print is do X=X*10+K; K++; coutccx; while(K !=4); O 112 121 O 123 O 112 12 O 1 12 123 O There is no right choice

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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If X iş an integer variable that I have yalue of o K9 is an integer
variable of value 1, then when executing the next piece of code,
the output of the prínt is
do
X=x*10+K;
K++;
coutc<X;
while(K !=4);
O 1 12 121
O 123
O 112 12
O 112 123
O There is no right choice
If 10 = 1, 5 = 1, and 7 = K are integer yariables, then when
you prínt the following code, the output is:
cout<<((I>K) && (J>K)) || (J<=K) || (K>=1)));
1
Wrong syntax that cannot be executed
There is no right choice
Typing the following sențence in C++ uses the
following injunction:
\"My Best Program Language"\?\C++
cout<<"\\\"My Best Program Language\"\\?
\\C++\\\n";
cout<<"\\"My Best Program Language\"\?
\C++\\n";
cout<<"\\My Best Program Language\"\\?
|\C++\\n";
cout<<"\\\"My Best Program Language\"\\?
|\C++\\n";
O There is no correct option
Transcribed Image Text:If X iş an integer variable that I have yalue of o K9 is an integer variable of value 1, then when executing the next piece of code, the output of the prínt is do X=x*10+K; K++; coutc<X; while(K !=4); O 1 12 121 O 123 O 112 12 O 112 123 O There is no right choice If 10 = 1, 5 = 1, and 7 = K are integer yariables, then when you prínt the following code, the output is: cout<<((I>K) && (J>K)) || (J<=K) || (K>=1))); 1 Wrong syntax that cannot be executed There is no right choice Typing the following sențence in C++ uses the following injunction: \"My Best Program Language"\?\C++ cout<<"\\\"My Best Program Language\"\\? \\C++\\\n"; cout<<"\\"My Best Program Language\"\? \C++\\n"; cout<<"\\My Best Program Language\"\\? |\C++\\n"; cout<<"\\\"My Best Program Language\"\\? |\C++\\n"; O There is no correct option
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