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Given values x 5, y = 1, count = 0 What is the value of x after the following code is executed ? count+=y; if (count <0 || count !=0 ) X--; else X++;

Given values x 5, y = 1, count = 0 What is the value of x after the following code is executed ? count+=y; if (count <0 || count !=0 ) X--; else X++;

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Given values x = 5, y = 1, count = 0 What is the value of x after the following code is executed ? count+=y; if (count <0 || count !=0 ) X--; else X++;
Transcribed Image Text:Given values x = 5, y = 1, count = 0 What is the value of x after the following code is executed ? count+=y; if (count <0 || count !=0 ) X--; else X++;
Expert Solution
Step 1

The complete program is given by:

#include <stdio.h>

int main()
{
    int x=5, y=1,count=0;
    count+=y;
    printf("Value of count is : %d \n", count);
    if (count<0 || count!=0)
    {
        x--;
        printf("Value of x is : %d", x);
    }
    else
    {
        x++;
        printf("Value of x is : %d", x);
    }
    

    return 0;
}

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