If X iş an integer variable that I have yalue of 0 K9 is an integer variable of value 1, then when executing the next piece of code, output of the prínt is do X=X*10+K; K++; coutecX; while(K !=4); O 112 121 O 123 O 1 12 12 O 112 123 O There is no right choice If 10 = 1, 5 = 1, and 7 = K are integer yariables, then when you print the following code, the output is: cout<((I>K) && (J>K)) || (J<=K) || (K>=1)); Wrong syntax that cannot be executed O There is no right choice Typing the following sențence in C++ uses the following injunction: \"My Best Program Language"\?\C++\ cout<<"\\\"My Best Program Language\"\\? \\C++\\\n"; cout<<"\\"My Best Program Language\"\? \C++\\n"; cout<<"\\My Best Program Language\"\\? \\C++\\n"; cout<<"\\\"My Best Program Language\"\\? |\C++\\n"; O There is no correct option

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