If x² + 2y +3z1 = x2 + 2y2 + 3z2 = x3 + 2y3 +3z3 =2, and x₂x3 +2y2y3 +3z2z3 = x3x1 +2y3v1 +3Z3Z1 = x1x₂ + 2y1y2 +3Z₁Z2 = 1, X₁ then find the value of x2 ₁ Y2 Z₁ Z2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 28RE
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If x² +2y+3z² = x² + 2y2 + 3z2 = x² + 2y3 +3z3 = 2, and x₂x3
+2y2y3 +3Z₂Z3 = x3x₁ + 2y3v₁ +3Z3Z1 = x₁x₂ + 2y₁₂ +3Z₁Z₂ = 1,
3₁2
x₁₂
then find the value of x₂
Z1
V2 Z2
Z3
X3 V3
Transcribed Image Text:If x² +2y+3z² = x² + 2y2 + 3z2 = x² + 2y3 +3z3 = 2, and x₂x3 +2y2y3 +3Z₂Z3 = x3x₁ + 2y3v₁ +3Z3Z1 = x₁x₂ + 2y₁₂ +3Z₁Z₂ = 1, 3₁2 x₁₂ then find the value of x₂ Z1 V2 Z2 Z3 X3 V3
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